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If a ball rolls off the edge of a table two meters above the floor and with an initial velocity of 20 meters per second what is the ball?
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A projectile is fired horizontally from a gun that is 71.0 m above flat ground emerging from the gun with a speed of 250 ms What is the magnitude of the vertical component of its velocity as it st?
If it's fired horizontally, then its initial vertical velocity is zero. After that, the vertical velocityincreases by 9.8 meters per second every second, directed downward, and the projectile hitsthe ground after roughly 3.8 seconds.Exactly the same vertical motion as if it were dropped from the gun muzzle, with no horizontal velocity.
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What is the value of constant horizontal velocity?
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
Sketch velocity-time graph when an object is thrown vertically upward?
Mark off the x-axis in seconds. Mark off the y-axis in meters per second. The graph is a straight line, starting at the origin, sloping down with a slope of -9.8 meters per second per second. It never gets above the x-axis, and 'y' is negative everywhere on the graph. That's because the velocity is always negative (speed directed downward).
A person jumps off a diving board 4.0m above the water's surface into a pool the person's downward motion stops 2.0m below the surface of the water estimate the avg. decleration of the person under wa?
so what you need to do is find the velocity that the person enters the water and then use the equation v sub final squared = v sub initial squared + 2*acceleration(final distance-initial distance). final velocity is zero, find the initial velocity yourself and use 2 as the final distance where the initial distance is 0, solve for acceleration. Easy way: the decelleration would have been twice that provided by gravity because the diver decellerated to zero in half the distance of the dive. The diver starts at zero and hits max velocity in 4 meters then goes from max velocity to zero in 2 meters. 2 x 9.81 m/s2 = ___
How do you calculate result?
AccelerationStep 1 Find the acceleration of the object, the time the object is being accelerated and the initial velocity. These values are usually given to you in the problem. If the force is given, find the acceleration by dividing the force on the object by its mass.Step 2 Convert all units to standard units. Acceleration should be in meters per second squared. Velocity should be in meters per second, and time should be in seconds.Step 3 Multiply the acceleration by the time the object is being accelerated. For example, if an object falls for 3 seconds, multiply 3 by 9.8 meters per second squared, which is the acceleration from gravity. The resultant velocity in this case is 29.4 meters per second.Step 4 Add this velocity to the initial velocity. In the example above, if the object had an initial velocity of 5 meters per second, the resultant velocity would be 34.4 meters per second. The overall formula here is v (final) - at + v (initial) where "v" is velocity, "a" is acceleration and "t" is time. In this example the equation would look like this: v (final) = 9.8 x 3 + 5, giving us a result of 34.4.After ImpactStep 1 Identify the initial velocity of the two objects, the mass of both objects and the final speed of either object if it is given. These values are usually given in the problem.Step 2 Convert all velocities to meters per second and all masses to kilograms.Step 3 Multiply the initial velocity of each object by its mass. Add these two products together to get the total momentum. For example, if both objects have a mass of 5 kilograms, one is at rest and the other is moving at 10 meters per second. The calculation would look like this: 5 x 10 + 5 x 0. This would give us a result of 50 kilogram-meters per second.Step 4 Divide the total momentum by the sum of the masses if the two objects stick together after impact. This will give you the resultant velocity of the two objects. In the example above, we would take 50 and divide by the sum of the masses, which is 10, getting a result of 5 meters per second.If the objects do not stick together, subtract the product of the mass and the final velocity of one object from the total initial momentum. Then, divide the difference by the mass of the other object. This will give you the resultant velocity of the other object. In the example from the previous step, if the final velocity of the object originally moving at 10 meters per second was 2 meters per second, our calculation would look like this: (50 - 10) / 5, which gives us a result of 8 meters per second.
Whats the equation for acceleration?
Acceleration=force divided by mass. The above is Newtons second law. Acceleration is also the change in velocity over the change in time, so it can also be stated as a=(final velocity - initial velocity)/(elapsed time)
When a ball is thrown vertically upward at initial velocity of 15 meter per second Find the position and velocity after 1.0 second and 40 second after leaving your hand?
1 sec : position = 10.1 metres above your hand, velocity = 5.2 ms^-1.40 sec : position = 7240 metres below your hand, velocity = 377 ms^-1 downwards.
What does it mean when final and initial velocity are the same?
Please help me I am the above person :(
Which information is needed to find the time a projectile is in motion?
The object's initial distance above the ground The object's initial velocity
A projectile is fired horizontally from a gun that is 71.0 m above flat ground emerging from the gun with a speed of 250 ms What is the magnitude of the vertical component of its velocity as it st?
If it's fired horizontally, then its initial vertical velocity is zero. After that, the vertical velocityincreases by 9.8 meters per second every second, directed downward, and the projectile hitsthe ground after roughly 3.8 seconds.Exactly the same vertical motion as if it were dropped from the gun muzzle, with no horizontal velocity.
How to Calculate the terminal velocity?
Terminal velocityThere is more than one explanation for terminal velocity, I think you are asking about a person or skydiver as opposed to a bullet.Terminal velocity is the velocity reached when the drag force equals the weight of the body minus the buoyant force, which halts acceleration and causes speed to remain constant.the terminal velocity of a skydiver in a normal freefall position with a closed parachute is about 120 mph or 54 m/s. This velocity is the asymptotic limiting value of the acceleration process, since the effective forces on the body more and more closely balance each other as it is approached. In this example, a speed of 50% of terminal velocity is reached after only about 3 seconds, while it takes 8 seconds to reach 90%, 15 seconds to reach 99% and so on.
What do you you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
How do you work out height from initial velocity final velocity mass and work done?
If you throw an object up, and assume that air resistance is negligible, knowing the initial velocity is enough. One way to do this is to use conservation of energy. Calculate the energy from the initial velocity, then insert it in the formula for gravitational potential energy.Same for final velocity - the final speed is the same as the initial speed. If you know the work done, you already have the first half of the above steps solved.
If a ball rolls off the edge of a table two meters above the floor and with an initial velocity of 20 meters per second what is the ball's acceleration and velocity just before it hits the ground?
The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
What is an acceleration of negative 20 meters per second squared?
A negative acceleration has the affect of decreasing the velocity of the moving object.If a plane is climbing at a speed of 100 meters per second and is subject to an acceleration of -20 meters per sec2 then after 1 second it's climbing speed will reduce to 80 mps, after 2 seconds to 60 mps .....and so on.This is illustrated by the law of motion v = u + ft, where u is the initial velocity, v is the final velocity, f is the acceleration and t is the time.How long does it take the plane to reach a zero climbing velocity.v = u + ft : 0 = 100 -20t : 20t = 100 : t = 5 seconds, which can be easily verified from the example a few lines above.
