If a neutral atom of sodium has 11 protons, it will have 11 electrons also.
The neutral atom of sodium has 11 electrons.
A neutral atom of sodium has 11 electrons. Sodium-25 refers to the isotope of sodium with 25 total protons and neutrons, so a neutral sodium-25 atom would still have 11 electrons to balance the 11 protons in the nucleus.
11 electrons in a neutrally charged atom of sodium . It is the same number as the number of protons and the Atomic Number. However, the sodium ion (NOT Atom) has lost one electron , so there are now 11 protons(+), and 10 electrons(-). Hence 11(+)10(-)= 1(+) Hence the sodium ion is written as 'Na(+)'.
The neutral atom of sodium has 11 protons because its atomic number is 11, which defines the element sodium on the periodic table. The number of protons in an atom determines its identity as a specific element; in this case, sodium. Since the atom is neutral, it also has 11 electrons, balancing the positive charge of the protons with an equal amount of negative charge from the electrons.
The sodium ion has less electrons than protons whereas the sodium atom has an equal amount of protons and electrons
Electrons~ 11 Neutrons~11 12Protons~11Youre welcome(;___________________________ (Improved answer) No, It has 11 electrons, 11 protons and 12 neutrons.
The number of electrons in a neutral atom is equal to the atomic number; sodium has 11 electrons. The number of protons is the same.
A neutral atom with 11 electrons would, by definition, have to have 11 protons. In this case, we are talking about Sodium.
Yes, sodium has 11 electrons. Sodium has 11 protons which balances out the negatively charged electrons in a neutral atom.
An element with 11 protons will have atomic number 11, or sodium. If the element has 11 neutrons, then it has an atomic mass of 11+11 = 22. Therefore, the isotope Sodium-22 has 11 protons, neutrons, and electrons.
In any neutral atom, the number of protons = the number of electrons.
A neutral sodium atom consists of 11 protons, 11 electrons, and usually 12 neutrons.