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120 kg-m/s
The Same! The statement above is true depending on what u mean. Think of it as a person running. While the person is running they have momentum ( momentum is mass times velocity). Now say they for some reason have to suddenly stop all at once, at the exact moment they stop the momentum is the same, this is why their body would jerk forward. However after that, when they were no longer moving, they would no longer have momentum, mathematically speaking that person's mass times their velocity of zero is then zero.
yes , look at a moving car or a walking person
This is conservation of momentum. You have the hot gases from the explosive charge along with the bullet moving out the barrel, away from the person. Momentum is mass times velocity. While the mass of the bullet and gases are small, the velocity is very high. So nothing was moving before the trigger was pulled, so net momentum is zero. After the trigger is pulled, the momentum is still net zero. Any momentum away from the gunner will have an equal momentum (the gun recoiling) toward him. Since the gun has much more mass than the bullet, the velocity is much less.
The four bobsled is heavier and has a greater mass. There will be more momentum, leading to greater velocity making it harder to stop.
120 kg-m/s
Momentum = mass x velocity Assuming you mean the rider is riding at 5 m/s, the momentum is 95 x 5, which is 475 kg-m/s
The Same! The statement above is true depending on what u mean. Think of it as a person running. While the person is running they have momentum ( momentum is mass times velocity). Now say they for some reason have to suddenly stop all at once, at the exact moment they stop the momentum is the same, this is why their body would jerk forward. However after that, when they were no longer moving, they would no longer have momentum, mathematically speaking that person's mass times their velocity of zero is then zero.
Momentum (p) = mass * velocity = 80 * 6 = 480 kg-m
Just multiply mass x velocity.
yes , look at a moving car or a walking person
This is conservation of momentum. You have the hot gases from the explosive charge along with the bullet moving out the barrel, away from the person. Momentum is mass times velocity. While the mass of the bullet and gases are small, the velocity is very high. So nothing was moving before the trigger was pulled, so net momentum is zero. After the trigger is pulled, the momentum is still net zero. Any momentum away from the gunner will have an equal momentum (the gun recoiling) toward him. Since the gun has much more mass than the bullet, the velocity is much less.
The four bobsled is heavier and has a greater mass. There will be more momentum, leading to greater velocity making it harder to stop.
The four bobsled is heavier and has a greater mass. There will be more momentum, leading to greater velocity making it harder to stop.
His speed is (500/60) m/s = 8-1/3 m/s .His velocity can't be completely specified using the information in the question.Its magnitude is 8-1/3 m/s. But in order to also state the direction of his velocity,we would also need to know the direction of his velocity.
Vectors have the magnitude and direction, scalars have only magnitude. Addition of vectors A and B will produce a vector C. Such that C=A+B. C is a vector because it will have magnitude and the direction.For an example consider a moving sidewalk such as those in the airports. If such a sidewalk is moving South at 2 miles per hour, its velocity is vector A. If a person walking on that sidewalk at 3 miles per hour also South, that persons velocity is vector B. However, that person will be moving at 2+3=5 miles per hour in relation to a stationary observer or in other words with the velocity of vector C.Further, consider A+B1=C1.If that person is walking North, or the opposite direction of treadmill's (if he or she got on the wrong sidewalk :) ), that person's velocity will be -3 miles per hour that will be vector B1. Thus in relation to a stationary observer that person is moving 2+(-3)=(-1) miles per hour towards South, the velocity of vector C1. That is the person is moving North at 1 mile per hour.
Momentum! Car has momentum before an accident, this momentum is transferred to the person after the car has made an abrupt stop (accident).