-- At the beginning, when it's dropped, its speed is zero.
-- At the end, when it hits the ground, its speed is 802.5 feet per second (547.2 mph).
-- During the 24.92 seconds when it's falling, its speed increases smoothly at the rate
of 32.2 feet per second faster every second than it was a second earlier.
These numbers are true if the rock is not falling through air. If there happens to be
air in some or all of its path, then the numbers are somewhat different, and they'd
depend on the shape, size, and weight of the rock. Even knowing those details ...
which you haven't included in the question ... a calculation in advance would be
fiendishly complicated, and the only real way to accurately predict the answer
would be to take the rock up to 10Kft, drop it, and time it.
The rock will hit the groud at the speed= squareroot(2x32.6x1000) = 256 feet/second.
an object will fall at around 50ft every second, so around 3 seconds.
32 ft per second squared- However, due to air resistance, the final speed will top out at about 250 mph for a streamlined object.
1800 ft min
s = 1/2 at^2 where a = 32 ft/sec/sec t = time = 6.27 seconds neglecting air resistance
Gravity and resistance (friction). Friction will only come into play on a fall from a long distance. This will be in the form of air resistance. If you are falling a short distance, gravity is the only force. The fastest you will be able to fall is at a rate of 9.81 ft/s^2.
its 10000 ft² its 10000 ft²
10000 * 9
100 ft * 100 ft = 10000 square feet.
has no clue
0.2296
10000 square feet are 929 square meters.
107,639.1 ft2
1.89 miles
an object will fall at around 50ft every second, so around 3 seconds.
10000 Imperial gallons = 1605 cu ft (to 4 sig fig)
3 feet = 1 yard so 10,000 ft = 3,333 yards and 1 foot.
Answer: 10,000 ft² = 0.229568 acres