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A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
The initial velocity is 0 metres/second.
Linear Velocity = Initial Velocity (m/s) + Acceleration (m/s2) * t 43.2 km/h
The plane's velocity at 10 seconds will be 150 meters per second or 335.54 mph
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
the answer is 24-9 m/sec. yuor welcome
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
The initial velocity is 0 metres/second.
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I am assuming the initial speed is 6.2 m/s Let upward motion be positive! Gravity decreases the speed by 9.8 m/s each second Acceleration due to gravity = -9.8 m/s each second (negative because gravity accelerates objects downward) Find time to reach the top of the path! Final velocity at the top = 0 m/s Initial velocity = 6.2 m/s Final velocity = Initial velocity + acceleration * time Time - = (final velocity - initial velocity) ÷ acceleration Time = (0 - 6.2) ÷ -9.8 = 0.633 seconds (to reach top) The path is symmetrical. 0.633 seconds to reach top and 0.633 seconds to reach glove again. Total time = 12.66 seconds
We can only give the mass of the object. Newton's second law of motion will show that Force = mass x acceleration. therefore 12 Newtons = 4 kilogrammes x 3 m/s2 To calculate final velocity you will need to specify the time, the acceleration (and the initial velocity).
a=change over velocity/time 60-initial velocity 45-final velocity 45-60= 15m/s 15/5= 3- acceleration
It will depend upon the initial velocity of the body. If 'u' be the initial velocity of the body, then the final velocity will be: v = u + at (v = final velocity, a = acceleration, t = time) i.e., v=u+10*7 = (u + 70) m/sec. If u=0 (i.e the initial velocity be zero) then final velocity, v=70 m/sec.
Initial velocity can be measured in the same units as any other velocity. In SI, that would be meters per second, but often km / hour are used, or (in a minority of countries) feet/second or miles/hour.
Linear Velocity = Initial Velocity (m/s) + Acceleration (m/s2) * t 43.2 km/h
anything shot up with that initial velocity. There isn't anything in specific.