The efficiency of the elevator can be calculated using the work input and work output. In this case, the work input is force x distance = 1200 N x 6 m = 7200 Nm, and the work output is force x distance = 1000 N x 6 m = 6000 Nm. Efficiency is work output / work input x 100%, so (6000 Nm / 7200 Nm) x 100% ≈ 83.3% efficient.
The tension can be greater than gravity when the elevator is accelerating downwards, causing a net force that exceeds the force of gravity acting on the elevator. This creates a situation where the tension in the elevator cable is greater than the force of gravity, allowing the elevator to move downwards.
Your weight in an elevator traveling upward at a constant speed would be the same as your normal weight on the ground. Weight is a measure of the force of gravity acting on an object, and as long as the elevator is not accelerating or decelerating, the gravitational force acting on you remains constant.
When an elevator is going up, the main forces acting upon it are the gravitational force pulling it downward and the tension in the elevator cable pulling it upward. Additionally, there may be a frictional force acting against the motion, depending on the smoothness of the elevator ride.
The force required to stop the elevator can be calculated using the equation F = m*a, where m is the mass of the person (80 kg) + mass of the elevator and a is the acceleration of the elevator (which is the velocity change divided by time). Once the force is calculated, it can be converted to the braking force needed by dividing it by 2, as each braked object resists the deceleration force equally.
To draw an elevator free body diagram, you would typically represent the elevator as a box with arrows showing the forces acting on it. Include the downward force of gravity acting on the elevator's mass and the normal force acting upward from the floor of the elevator to support it. If the elevator is accelerating or decelerating, also include a force arrow in the direction of acceleration or deceleration.
The tension can be greater than gravity when the elevator is accelerating downwards, causing a net force that exceeds the force of gravity acting on the elevator. This creates a situation where the tension in the elevator cable is greater than the force of gravity, allowing the elevator to move downwards.
Weight of the elevator = 1000kg x -9.8m/s2 = -9800N Upward force acting on the elevator = 1000kg x 2m/s2 = 2000N Net force = upward force - weight of elevator = 2000N - (-9800N) = 11800N
Yes, when a woman pushes an elevator button, she is exerting a force by applying pressure to the button. This force is what activates the elevator mechanism to move to the desired floor.
Your weight in an elevator traveling upward at a constant speed would be the same as your normal weight on the ground. Weight is a measure of the force of gravity acting on an object, and as long as the elevator is not accelerating or decelerating, the gravitational force acting on you remains constant.
The two forces acting on a person in an elevator are gravity pulling the person down and the elevator floor pushing the person up. These forces are equal when the elevator is moving at a constant speed or when it is stationary. They are not equal when the elevator is accelerating or decelerating.
When an elevator is going up, the main forces acting upon it are the gravitational force pulling it downward and the tension in the elevator cable pulling it upward. Additionally, there may be a frictional force acting against the motion, depending on the smoothness of the elevator ride.
The force required to stop the elevator can be calculated using the equation F = m*a, where m is the mass of the person (80 kg) + mass of the elevator and a is the acceleration of the elevator (which is the velocity change divided by time). Once the force is calculated, it can be converted to the braking force needed by dividing it by 2, as each braked object resists the deceleration force equally.
To draw an elevator free body diagram, you would typically represent the elevator as a box with arrows showing the forces acting on it. Include the downward force of gravity acting on the elevator's mass and the normal force acting upward from the floor of the elevator to support it. If the elevator is accelerating or decelerating, also include a force arrow in the direction of acceleration or deceleration.
No work is done on a person ascending an elevator as the force is in the same direction as the displacement, resulting in zero work done by the force moving the person.
As the elevator moves upward, the reading on the scale will temporarily increase. This is because the scale measures the force exerted by the person standing on it, which includes their weight and an additional force due to the upward acceleration of the elevator.
Force = mass * acceleration Since the only force acting on the elevator is gravity, the force is 1000*9.81 = 981N Towards the ground Note that it is essential to put the direction that the force is acting as it is a vector quantity.
The force acting on the elevator is equal to its weight, which can be calculated using the formula F = m * g, where m is the mass of the elevator (1000 kg) and g is the acceleration due to gravity (9.8 m/s^2). So, the force on the elevator would be 1000 kg * 9.8 m/s^2 = 9800 N.