The efficiency of the elevator can be calculated using the work input and work output. In this case, the work input is force x distance = 1200 N x 6 m = 7200 Nm, and the work output is force x distance = 1000 N x 6 m = 6000 Nm. Efficiency is work output / work input x 100%, so (6000 Nm / 7200 Nm) x 100% ≈ 83.3% efficient.
In an elevator free body diagram, the key components are the elevator itself, the tension in the supporting cable, the force of gravity acting on the elevator and its occupants, and the normal force exerted by the floor of the elevator. The forces involved include the tension in the cable, the force of gravity pulling the elevator down, and the normal force pushing the elevator and its occupants up.
The force of gravity has the greatest magnitude on you as you accelerate upward in an elevator.
The tension can be greater than gravity when the elevator is accelerating downwards, causing a net force that exceeds the force of gravity acting on the elevator. This creates a situation where the tension in the elevator cable is greater than the force of gravity, allowing the elevator to move downwards.
The normal force in an elevator is equal to the apparent weight of an object. As the elevator moves up or down, the normal force changes, affecting the apparent weight experienced by the object.
If the elevator's speed is constant (acceleration is zero), regardless of whether it's up or down,then your weight in it is the same as your normal weight on the ground.It should be easy to carry a bathroom scale onto an elevator with you some day and check it out.
In an elevator free body diagram, the key components are the elevator itself, the tension in the supporting cable, the force of gravity acting on the elevator and its occupants, and the normal force exerted by the floor of the elevator. The forces involved include the tension in the cable, the force of gravity pulling the elevator down, and the normal force pushing the elevator and its occupants up.
The force of gravity has the greatest magnitude on you as you accelerate upward in an elevator.
The tension can be greater than gravity when the elevator is accelerating downwards, causing a net force that exceeds the force of gravity acting on the elevator. This creates a situation where the tension in the elevator cable is greater than the force of gravity, allowing the elevator to move downwards.
The normal force in an elevator is equal to the apparent weight of an object. As the elevator moves up or down, the normal force changes, affecting the apparent weight experienced by the object.
Weight of the elevator = 1000kg x -9.8m/s2 = -9800N Upward force acting on the elevator = 1000kg x 2m/s2 = 2000N Net force = upward force - weight of elevator = 2000N - (-9800N) = 11800N
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If the elevator's speed is constant (acceleration is zero), regardless of whether it's up or down,then your weight in it is the same as your normal weight on the ground.It should be easy to carry a bathroom scale onto an elevator with you some day and check it out.
When the elevator is still the force of gravity due to your weight pressing downwards on the floor is equalled exactly by the floor pushing you upwards with the same force. When the elevator rises you feel a little heavier, and the elevator is pushing upwards with the same increased force. When the elevator descends you feel that you lose a little weight, and the floor pushes up at you with the equally reduced force, so you descend.
When an elevator is going up, the main forces acting upon it are the gravitational force pulling it downward and the tension in the elevator cable pulling it upward. Additionally, there may be a frictional force acting against the motion, depending on the smoothness of the elevator ride.
The force required to stop the elevator can be calculated using the equation F = m*a, where m is the mass of the person (80 kg) + mass of the elevator and a is the acceleration of the elevator (which is the velocity change divided by time). Once the force is calculated, it can be converted to the braking force needed by dividing it by 2, as each braked object resists the deceleration force equally.
The solution to the physics elevator problem involves calculating the net force acting on the elevator and using Newton's second law to determine the acceleration of the elevator. By considering the forces of gravity, tension in the cable, and the normal force, one can find the acceleration and ultimately solve the problem.
Draw an arrow pointing upwards for the tension force and an arrow pointing downwards for the weight of the elevator which will be its mass times gravity (mg). Also, draw another arrow pointing downwards for any mass that may be inside the elevator (another mass times gravity arrow but for a separate weight) and add that value to that of the weight of the elevator. Depending on the direction that the elevator is moving (up or down) draw another arrow respectively and label it "a" for acceleration.