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If at a party there are twelve people present Everyone has to shake hands exactly once with every other person How many handshakes are necessary?
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∙ 14y ago
Sixty-six unique, distinct handshakes.
Wiki User
∙ 14y ago
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How many handshakes will there be in total if 10 people shake hands with each other?
"Each other" leaves this very open-ended; that depends on if A shakes with B or A shakes with B & C, OR if A shakes with all the other nine, etc. I would say the answer would have to be one of two: 10 or 100. If each person chooses only one to shake with, it would be ten. IF each person shakes with everyone there, all ten, it would be 100. Since this question is pretty vague, Some people may come to the conclusion that the answer is Either 90 assuming everybody stayed to shake hands with each other meaning the first person shook hands with 9 people and the 2nd person did the same etc etc bringing it to the conclusion that you got 90 handshakes. Another answer towards for people would be 45 being that the first person gave a hand shake to 9 people and then left and then the 2nd person gave a handshake to 8 people n then left etc and etc making it 9+8+7+6+5+4+3+2+1=45. A very simple formula can be applied here. no. of handshakes= (n(n-1))/2 where n is the no.of people present Another conclusion i think the answer is, is the simplest conclusion you can come up with; at the end of the banquet 10 people shake hands with each other so how many handshakes were passed on? 5 hand shakes were given cause that way 10 people did give a hand shakes and since it takes 2 to give out a handshake 5 hand shakes were given. The phrase "Each other" is inclusive, meaning that every person shakes the hand of every other person at the end of the banquet. And since the handshakes that occur when person 1 shakes person 2's hand and vice versa, are the same handshake, those handshakes only count as one entire handshake. This holds true with every other handshake between every other person at the banquet. With this is mind, there will be 45 handshakes since person 1 will shake 9 other people' hands, then person 2 will shake 8 other people's hands, and so on. It would look like this on paper: 9+8+7+6+5+4+3+2+1=45. Each of the 10 people shakes hands with 9 others. If you multiply that, you are counting each handshake double. Therefore, the calculation is 10 x 9 / 2.
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'Have' is of the verb 'to have'. 'is' is of the verb 'to be'.
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Have can be used as a main verb:I have lunch at 1:00pm.This sentence is present simple. It is about something that is true at the moment or possibly something that I do again and again ie a habit.The verb phrase have had is used to make present perfect:I have had lunch.This sentence is present perfect and is about something that has happened (completed) in the recent past and has possibly has some significance now in the present. Have is an auxiliary verb had is the main verbDo you want lunch?No thanks I have had lunch.
How many handshakes will there be altogether at the end of a business conference with five people present?
9 handshakes if everyone shakes everyones hand once
There are 3 people at a party If each person must shake hands with every other person at the party exactly once how many handshakes will there be?
With 3 people, there are only 3 handshakes: AB, AC, and BC. Where it gets interesting is at a party with, say, 10 people ... 45 handshakes. Or in the US Senate when all 100 Senators are present ... 4,950 handshakes.
How many handshakes will there be altogether at the end of a business conference if the ten people present all shake hands with each other once?
There will be 45 handshakes (assuming that each person doesn't repeat who they shake hands with). Use the following formula for this one (n*(n-1))/2 where n is number of people...so if 10 people its (10 x 9) / 2 = 45 handshakes, if 7 people its (7 x 6) / 2 = 21 handshakes etc.
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If every person at a party shakes the hand of every other person and there were 105 handshakes in all How many persons were present at the party?
The answer is 15 people. Each shook hands with 14 others, and there are half that many handshakes (pairs). The total number of pairs (distinct handshakes) within the group is defined by the formula T = [n!/(n-2)!] /2 Given T = 105 we get n!/(n-2)!=210 which implies n(n-1)=210 on solving we get n=15
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