The only way current can increase while resistance in a circuit increases is if voltage, which is the force that causes electric current, increases.
Resistance increases as temperature increases. If Voltage is held constant then according to Ohm's Law Voltage = Current x Resistance then current would decrease as resistance increases.
If current increases, then voltage also has to increase, assuming that resistance stay relatively the same. Power will also increase. Since power is the product of voltage and current, then the power increase would be the square of the voltage or current change.
There is an electronic formula voltage/resistance = current If you translate this into plumbing terms voltage would equal water pressure resistance would equal pipes and valves and the current would equal the flow rate. If you start closing a valve it increases resistance and lowers the current flow
10 volts applied to 5 ohms would cause a current flow of 2 amperes. Current = voltage divided by resistance.
First, this statement stands as long as voltage is constant. If you held the current constant then power would increase as resistance increases.V=IR. For a fixed voltage if you increase the resistance (R) then the current (I) will decrease - following the formula.Power = VI so as the resistance increases the value of VI (power) decreases as V is constant and I gets smaller.Therefore the power is decreasing as the resistance increases (when voltage is held constant).Hope this helps.
If current increases, then voltage also has to increase, assuming that resistance stay relatively the same. Power will also increase. Since power is the product of voltage and current, then the power increase would be the square of the voltage or current change.
Because by increasing the load resistance, the total circuit resistance is reduced. This means with less resistance, there is more current drawn from the source. Doubling the size of a load resistor increases the load current.
The electrical potential energy increases as the voltage is increased. It further excites the filament in the bulb more than a lessor voltage would. Using good old ohm's law (Voltage = Current x Resistance), a larger voltage applied to a bulb at the same resistance increases the current proportionally and larger currents has the effect to cause higher temps in conductors
For a fixed resistance (ohms) current increases as voltage increases. Since Watts equals Volts x Amps x Power Factor then Watts would increase as voltage increases. The resistance would usually be fixed, but if you had a variable load resistance as the resistance decreased and the voltage remained constant, the current would increase and watts would therefore increase. Watts = Volts x Amps x Power Factor Volts = Amps x Ohms Power Factor is 1 for a resistive load.
Current decreasesWhen voltage remains constant and resistance increases the current in the circuit will reduce.More informationV=IRwhere V is voltage,I is current andR is resistance.From the above equation,R=V/I, and hence resistance is indirectly proportional to current.Therefore, an increase in resistance would have the effect of decreased current.NB: this holds true only as long as the voltage remains constant.Another opinionHowever, this is only true in the case of a circuit connected in series.When circuits are connected in parallel, the opposite happens. If there is an increase in the amount of resistors in parallel, the total resistance of the circuit then decreases and the current increases subsequently.Yet another viewNo, that's not stated right.If more resistors are added in parallel - so that the circuit's overall total resistance decreases and its total current increases - that is NOT in any way the opposite of what this question is asking about...Let's make this crystal clear, so that there is no confusion: "an increase in the amount of resistors" is NOT the same as "an increase in resistance".So a parallel circuit behaves EXACTLY the same as a series circuit: if its overall resistance increases, the overall current going through the parallel circuit decreases AND if its overall resistance decreases, the overall current going through the parallel circuit increases.Actually, the second opinion is correctIn a parallel circuit, there are more branches to allow electrons back to the power supply, so current increases. With more resistors in a circuit, the overall resistance in a parallel circuit DECREASES.In a series circuit, current is the same throughout. So if more resistors are added, resistance INCREASES and so current DECREASES.
Ohm's Law says Voltage = Current x Resistance With constant voltage, an increase in resistance decreases the current. Now the load can be added in two basic ways. If the load is added in series the resistance will increase. If you add load in parallel the resistance will decrease and the current will increase from the source.
If the filament really was made from a material that has a negative temperature coefficient (as temperature increases, resistance decreases) then the decreasing resistance would cause more and more current to be taken as the lamp heated up and the temperature would get higher and higher in a runaway manner until either the power supply's breaker would trip or (more likely) the light bulb's filament would simply burn open. In fact the filament has to be made from a material that has a positive temperature coefficient. (As temperature increases, resistance increases.) Then, as the bulb's temperature rises, its filament's increasing resistance causes less current to be taken than when it was cold. Quite quickly a stable "steady-state" temperature and "running" resistance is reached so that the bulb simply continues to give out a steady amount of light according to the current it is taking from the electricity supply.