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If f(x)=x2+10, then f(x+h)=?

f(x+h)=(x+h)2+10 (since f(x)=x2+10, substitute the x in x2 to (x+h)2)=(x+h)(x+h)+10 (then multiply (x+h) by (x+h) by doing the FOIL method)=x2+xh+xh+h2+10 (First: x*x, Outside: x*h, Inside: h*x, Last: h*h)=x2+2xh+h2+10 (combine like terms (xh+xh=2xh))

So if f(x)=x2+10, then f(x+h)=x2+2xh+h2+10

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1f+7=12 is the equation so, f=5

f(x) = x2 + 5x + 1 The roots of this equation are x = -0.2087 and x = -4.7913 (approx).

If: df+10f = 3 Then: f(d+10) = 3 And: d = 3/f -10

F = 9/5 C + 32 = (9/5) x 10 + 32 = 18 + 32 = 50

find f'(x) and f '(c)f(x) = (x^3-3x)(2x^2+3x+5

f(x) = x2 + 3 g(x) = x + 3 f(g(x)) = g(x)2 + 3 = (x + 3)2 + 3 = x2 + 6x + 12

So what is the question?

That's going to depend on the values of 'a', 'b', 'c', and 'f'.

F(x) = 15x2 - 2.5 + 3 That's a quadratic or 2nd degree polynomial in x.

119+246+f = 893 f = 893-119-246 f = 528

92.47 + f = 105 f = 105 - 92.47 f = 12.53

No, f(x) is not the inverse of f(x).

f(x) = x2 + 5x + 6At a critical point, f'(x) = 0.f'(x) = 2x + 5 = 02x = -5x = -2.5f(-2.5) = (-2.5)2 + 5(-2.5) + 6 = (6.25) - (7.5) + (6) = 4.75

A = 2 means that T + 2 = F, which means T = F - 2. And A = 2 also means that 2 + B = Z. This means that 2 + B + P = T. Since this is true, it is also true that 2 + B + P + F = T + F. And since B + P + F = 24, it is true that 2 + 24 = T + F ,which means T + F = 26. Since F = T + 2, it is true that T + T + 2 = 26. So T = 12. And since Q - T = 7, it is true that Q = 19.

âˆ« f'(x)/(p2 + q2f(x)2) dx = [1/(pq)]arctan(qf(x)/p)

y = f(x) = 2x2 - 3x + 10dy = (4x - 3) dxNote:It's possible that the function in the question may have been f(x) = (2x)2 - 3x + 10 .If that's the case, thendy = (8x - 3) dx

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", A critical phrase (less than/greater than) is missing between "-10" and "or".

No. -10 F = -23.33 C -37 C = -34.6 F

s=5 f+s=? Substitute 5 in for s.Substitute 1 in for f.f+s=f+5f=11+5 ={6}

It would be 7.

No, by itself it is not.

f(x) = 3x2 + 5x + 2fprime(x) = 6x + 5

Minus 10 °F = Minus 23 °C

Yes. This Formula is known as Euler's Thereom.

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