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Short answer:Yes.Long answer:If friction is neglected, then the two masses will hit ground at the same time.This because of the gravity, and gravity is constant.If you however make one test of this at a very very high altitude, the gravity would be less and the objects would take longer to fall 3 meters.It does not matter if one object is gold and the other object is a feather.With no friction and same circumstances otherwise, they will fall equally fast.
Because of gravity, objects fall at 9.7m/s making them reach the ground at the same time. This does not apply to objects like paper or feathers due to the fluid friction in the air.
If friction due to air is neglected then both 10kg and 100 kg would reach the ground level at the same time. In the expression S = ut + 1/2 g t^2 we don't have place for mass. Hence for same S, with same g for both masses, it would have the same t
It is air friction. An aeroplane flying into a headwind will use up much more fuel than an aeroplane flying with a tailwind. Air friction means that a feather would take much longer to reach the ground than a lead weight dropped from the same height. Yet, if the feather and the lead weight were to be dropped in a vacuum (not subjected to air resistance) they would both reach the ground at the same time.
So she can reach faster
both masses have the same speed. The acceleration of objects in freefall is independent of mass, resulting in the same speed at the end of a fall. The momentum and energy are proportional to the mass.
Short answer:Yes.Long answer:If friction is neglected, then the two masses will hit ground at the same time.This because of the gravity, and gravity is constant.If you however make one test of this at a very very high altitude, the gravity would be less and the objects would take longer to fall 3 meters.It does not matter if one object is gold and the other object is a feather.With no friction and same circumstances otherwise, they will fall equally fast.
They would hit the ground at the same time.
Because of gravity, objects fall at 9.7m/s making them reach the ground at the same time. This does not apply to objects like paper or feathers due to the fluid friction in the air.
science reach the masses
If friction due to air is neglected then both 10kg and 100 kg would reach the ground level at the same time. In the expression S = ut + 1/2 g t^2 we don't have place for mass. Hence for same S, with same g for both masses, it would have the same t
Precipitation that does not reach the ground is called 'virga'. If it does reach the ground, it's called 'praecipitatio'.
No Because of massrate of acceleration, if they have the same outer shape (for friction) then they will reach the ground at the same time regardless of weight
You must let the lighter one go first then let the heavier one go. The heavier should then catch up.
It is air friction. An aeroplane flying into a headwind will use up much more fuel than an aeroplane flying with a tailwind. Air friction means that a feather would take much longer to reach the ground than a lead weight dropped from the same height. Yet, if the feather and the lead weight were to be dropped in a vacuum (not subjected to air resistance) they would both reach the ground at the same time.
So she can reach faster
In vacuum they reach ground exactly at the same time. In a medium other than vacuum the ball will reach ground first.