Half life has unit. That is unit of time. So it has to be mentioned. Let us assume that half life is 1 year. Okay. Now to know about the mass remaining we have to get the ratio (1/2)^1620. Hence remaining will be 1/(2^1620) * mass at the beginning
1 / 26 = 1 / 64.
No. In two half-lives, a radioactive isotope will decay to one quarter of its original mass. In one half-life, one half of the mass decays. In the next half-life, one half of the remaining mass decays, and so on and so forth. At each half-life point, you would see 0.5, 0.25, 0.125, 0.0625, etc. remaining. The logarithmic equation is... AT = A0 2(-T/H)
One sixteenth of a gram. 1st halflife- 1/2 gram 2nd, 1/4 3rd 1/8th 4th halflife, 1/16th
The Terbium isotope found in nature (159Tb) is stable. Like all elements, Terbium has radioisotopes, of which 33 have been created to date. 158Tb is the most stable of these, with a half-life of 180 years, 157Tb has a 71 year half-life. 160Tb has a half-life of 72.3 days. Most of the remaining radioisotopes have half-lives that are less measured in seconds, although some have half lives that are measured in days.
After 300 years: 50% gone, 50% remaining. After another 300 years: half of the 50% remaining is gone = 25% of the original sample. 25% of the original remains. So, after 600 years, 3/4 is gone, 1/4 remains.
12.5% is remaining.
Fraction remaining = 0.5^n where n = # of half lives that have elapsed60 yrs x 1 half life/12 yrs = 5 half lives have elapsed Fraction remaining = 0.5^5 = 0.03125 mass remaining = 0.03125 x 80.0 g = 2.5 g remaining
1/24 = 1/16
1 / 26 = 1 / 64.
3 At the end of the first half life, there will theoretically be 50% remaining. 2 half lives: 25% 3 half lives:12.5 %
After 6 half lives, the remaining will be (1/2)6 i.e 1/64 th of the initial amount. Hence by percentage it would be 1.5625 %
half life is 8.1 days, so it takes 8.1 days for half the iodine sample to decay. It takes another 8.1 days for half of the remaining sample (ie. 1/4th of the original sample) to decay. So it takes 16.2 days for 3/4th of the sample to decay.
No. In two half-lives, a radioactive isotope will decay to one quarter of its original mass. In one half-life, one half of the mass decays. In the next half-life, one half of the remaining mass decays, and so on and so forth. At each half-life point, you would see 0.5, 0.25, 0.125, 0.0625, etc. remaining. The logarithmic equation is... AT = A0 2(-T/H)
One sixteenth of a gram. 1st halflife- 1/2 gram 2nd, 1/4 3rd 1/8th 4th halflife, 1/16th
The half-life of an atom is how long it takes for half of the atom's mass to radioactively decay. This occurs exponentially; therefore, after 2 of the atom's half-lives have passed, 3/4 of the atom will have decay (half during the first half-life, then half of the remaining mass, or one quarter, during the second).
The Terbium isotope found in nature (159Tb) is stable. Like all elements, Terbium has radioisotopes, of which 33 have been created to date. 158Tb is the most stable of these, with a half-life of 180 years, 157Tb has a 71 year half-life. 160Tb has a half-life of 72.3 days. Most of the remaining radioisotopes have half-lives that are less measured in seconds, although some have half lives that are measured in days.
6 hours = 2 half lives, thus 25 % would remain. 0.25 x 2 mg = 0.5 mg.Done another way...fraction remaining = 0.5^n where n = number of half lives = 6hr/3hr = 2fraction remaining = 0.5^2 = 0.250.25 x 2 mg = 0.5 mg