Half life has unit. That is unit of time. So it has to be mentioned. Let us assume that half life is 1 year. Okay. Now to know about the mass remaining we have to get the ratio (1/2)^1620. Hence remaining will be 1/(2^1620) * mass at the beginning
After 4 half-lives, the amount remaining is ( (1/2)^4 ), which equals 1/16. Therefore, 1 gram of radium-226 will have 1/16 gram unchanged after four half-lives, which is 0.0625 grams.
After two half lives, 25% of the original carbon-14 would remain. This is because half of the remaining carbon-14 decays during each half life, leaving you with 50% after one half life and 25% after two half lives.
If a radioisotope undergoes six half-lives, only (1/64) or (0.015625) of the original radioisotope remains, because half of the remaining material decays at each half-life.
One sixteenth of a gram. 1st halflife- 1/2 gram 2nd, 1/4 3rd 1/8th 4th halflife, 1/16th
After three half-lives, 12.5% of the original radioactive material will remain. Each half-life reduces the amount of material by half, so after three half-lives the remaining material will be 0.5^3 = 0.125 or 12.5%.
After 4 half-lives, the amount remaining is ( (1/2)^4 ), which equals 1/16. Therefore, 1 gram of radium-226 will have 1/16 gram unchanged after four half-lives, which is 0.0625 grams.
After three half-lives, 12.5% of the radioactive isotope is remaining. This is because each half-life reduces the amount of radioactive material by half.
After two half lives, 25% of the original carbon-14 would remain. This is because half of the remaining carbon-14 decays during each half life, leaving you with 50% after one half life and 25% after two half lives.
If a radioisotope undergoes six half-lives, only (1/64) or (0.015625) of the original radioisotope remains, because half of the remaining material decays at each half-life.
To calculate the amount of thorium remaining after 2 half-lives, you use the formula: amount = initial amount * (1/2)^n, where n is the number of half-lives. If we assume the initial amount is 1 gram, after 2 half-lives, there would be 0.25 grams of thorium remaining.
After 2 half-lives, you would have 25% of the original amount remaining. Each half-life reduces the amount by half, so after two half-lives, you would have 25% left (50% reduced by half twice).
1/24 = 1/16
Based on the half-life of Na-24, after 1 half-life (15 hours), there would be 500 atoms remaining. After 2 half-lives (30 hours), there would be 250 atoms remaining. After 3 half-lives (45 hours), there would be 125 atoms remaining in the sample.
3 At the end of the first half life, there will theoretically be 50% remaining. 2 half lives: 25% 3 half lives:12.5 %
After 5 half-lives, 3.125% (or 1/2^5) of a radioactive sample remains. Each half-life reduces the sample by half, so after 5 half-lives, there is only a small fraction of the original sample remaining.
Fraction remaining = 0.5^n where n = # of half lives that have elapsed60 yrs x 1 half life/12 yrs = 5 half lives have elapsed Fraction remaining = 0.5^5 = 0.03125 mass remaining = 0.03125 x 80.0 g = 2.5 g remaining
One sixteenth of a gram. 1st halflife- 1/2 gram 2nd, 1/4 3rd 1/8th 4th halflife, 1/16th