Since there are 6366 hours in a year, 1930 kWh is about 0.3 kW per hour. (1930 / 6366)
Most 120 Volt appliances have their Watts listed somewhere on the appliance. Divide this number by 1,000 to get kilowatts. Determine the rate you are charged for electric power. Your electric bill will tell you how many kWh(kilowatt hours) you use, and what the total charge is. Divide your total charge ($?) by the kWh used. In northern Illinois, we are charged about $0.11 per kWh. Multiply the number of hours the appliance is used by its power consumption in kilowatts. This gives you the number of kWh the appliance used. Then multiply that kWh value by the rate for your area that you determined from your electric bill. That will be the cost for the number of hours the appliance was on. Example: If I toast 2 slices of bread in my toaster, it takes about 3 minutes, or 0.05 hours. My electric bill is $61.38 and I used 558 kwh for that month. Dividing $61.38 by 558, I get about $0.11 per kWh. So, I divide my toaster Wattage (750) by 1,000 to get 0.75 kW. So now I can multiply the hours that the appliance was used (0.05) by its power consumption rate in kW (0.75). This result is 0.0375 kWh of energy used. Then I can multiply the rate the electric company charges ($0.11) by the energy used (0.0375 kWh). The final result is $0.004125.
Your question should read, "How many kW.h are there in 0.07 GW.h?" It's important to use the correct symbols. There are 1000 000 000 kilowatt hours in one gigawatt hour -so you can now work it out for yourself.
There are two measures of electricity to know about: kWh, and kW. kWh, or kilowatt-hours, is a measure of total energy use over time. It's like how far you've driven your car. kW, or kilowatts, is a measure of instantaneous consumption, like how fast you are driving at any given second. The average home in Phoenix might max out at around 3 kW or a little more when everything - your computers, refrigerator, lights, air conditioning, etc. - are running. (An individual hair dryer might use 1.5 kW, so don't run those too long.) kW, however, is not how you get billed. Almost all residential properties get billed on kWh, the total amount of electricity they use each month. kWh can be calculated by multiplying kW by the number of hours you used that kW. This is the same as figuring out how far you've driven by multiplying your speed by how much time you spent driving at that speed. In Phoenix, an average house your size might use around 30-40 kWh every day. It could be twice this in the summer when you're air conditioning, and much less in the fall or spring when you're not.
It depends on where you live. You want to know how much Sun you get (solar hours). If you live in Southern California or Arizona, you might get 6 hours per day. If you live in Northern CA or Oregon, it might be closer to 4. First, you take your 1,000 kWh/mo and divide that by 30 to get your kWh/day. 1,000 / 30 = 33.3 kWh/day Then you divide this by the number of solar hours per day your area gets. Let's say 5. 33.3 / 5 = 6.67 kW Last you need to adjust for real world inefficiencies. A good rule of thumb is to suppose approximately 75% - 80% inefficiencies. So increase your system a little. 6.67 kW / 0.75 = 8.9 kW. This is a fairly large residential system, but you can reasonably expect it to cover 100% of your electricity needs if you use 1,000 kWh per month. Want to know how much an 8.9 kW solar system might cost? Go to and play the solar calculator in the related link below. (Yes, it's free.)
There are two things missing in this question. The period of time the 1000 watts is being used and the price that you are paying for a kWh. If the 1000 watts was left on for an hour it would be 1 kWh. The cost per kWh is still needed, so it can be multiplied the the 1 kWh, to find a cost.
Over 640,000 on the average
40-60 depending on what time of year it is.
2000w usually it is but it differs from the size and quality of the device.
100 kWh
about 10,000 KWh
400 Kwh per year (1996 - 120 liters)
New energy star models are about 470 kWh per year.
To find kWh a time frame has to be given. That is what the h in kWh stands for.
24 kwh per day
About 3 kWh's of heat are created for every kWh of electricity it consumes
455.1 billion kWh per year
In ten hours, a 200W bulb will use: 10 * 200 = 2000 Watt-hours = 2 kwh