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If the atmospheric pressure is 106.7 kPa what is the difference in the height of the two arms of the mercury barometer in mm of Hg?
Nataliemariedionne
Assume one arm contains a "vacuum" trapped in a sealed end and the other arm is open to the atmosphere. Then the difference in height depends on the atmospheric pressure.
Net pressure exerted by the longer Hg column = rho * g * h, where rho = the density of Hg = 13.534 [g/cm3] ; g = the gravitational constant = 9.8 [m/s2]; and h = the difference in height [m].
Therefore, 106.7 [kPa] = 13.534 [g/cm3] * 9.8 [m/s2] * h; or
106.7x103 [N/m3] = 13.534 * 103 [kg/m3] * 9.8 [m/s2] * h [m].
Rearranging, we have h = 0.804 [m]
Q.E.D.
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∙ 14y ago
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