Work=Distance/Time so even thought the force is greater it does not factor into the formula unless the size of the piston affects the time or the distnce the work is being done in. I imagine a larger force from the piston merely makes it easier for the engine to work at the same workload and or achieve a greater work formula with the force being factored into its own formula.
Work is the product of (force) x (distance).If, as you allege, the force increased but the work didn't change, thenthe distance must have decreased, by exactly the same factor as theincrease in the force, so that their product is not changed.
In a hydraulic system, the force on the applying piston is multiplied by the reciprocal of the area of the piston, to find pressure which is multiplied by the piston area.
You get the force exerted by a hydraulic piston by taking the pressure times the surface area of the piston.
The piston of a gauge pressure rotating until its freely suspend because the weight of the piston is balanced by the centrifugal force. The centrifugal force is created by the rotation of the piston and is equal to the weight of the piston.
True!!!
it depends on the surface ratio, if both small pistons have the same surface area, then the same amount of force will be applied.
A piston with a small surface area, is used to push fluid through a pipe, to a piston with a large surface area.The force used to push the small piston, will be divided into the larger surface area of the second piston.The larger piston will move a smaller amount, but will have more force, proportional to the difference in sizes.
Suppose the smaller piston was 1 square cm and the large piston was 7 square cm. If you pushed on the small piston, the force would be multiplied 7 times on the large piston. The Hydraulic System is a system that uses liquids to transmit pressure and multiply force in a confined fluid. Hope this helped. (:
A hydraulic system multiplies force by applying the force to a small surface are. The increase in pressure is then transmitted to another part of the confined fluid, which pushes on a larger surface area
33,250.
First the driver puts pressure in the foot brake, which then pushes a small piston, the piston then exerts pressure in the brake fluid. Then the increased pressure is transmitted through the fluid in the brake lines to a larger piston within the wheels of the car. Each piston pushes in a brake pad which the rubs against the brake disc, and the wheels motion is slowed down by the force of friction.
By using a lever or a pulley. But the reduced force must then act through an increased distance.
Work is the product of (force) x (distance).If, as you allege, the force increased but the work didn't change, thenthe distance must have decreased, by exactly the same factor as theincrease in the force, so that their product is not changed.
In a hydraulic system, the force on the applying piston is multiplied by the reciprocal of the area of the piston, to find pressure which is multiplied by the piston area.
You get the force exerted by a hydraulic piston by taking the pressure times the surface area of the piston.
The piston of a gauge pressure rotating until its freely suspend because the weight of the piston is balanced by the centrifugal force. The centrifugal force is created by the rotation of the piston and is equal to the weight of the piston.
hydrauchloric jacks work on this principle when a small force is applied to one end of a movable piston a large force over a larger area on the other side raises the car to a height