If a machine has 100 percent efficiency, the output work = the input work. That's actually basically what the efficiency of a machine is - output work / input work * 100.
Output/Input * 100= %
In theory, work output might be equal to work input; that would be 100% efficiency. In practice, the output of a machine will be less than the input; i.e., some energy will be lost.In theory, work output might be equal to work input; that would be 100% efficiency. In practice, the output of a machine will be less than the input; i.e., some energy will be lost.In theory, work output might be equal to work input; that would be 100% efficiency. In practice, the output of a machine will be less than the input; i.e., some energy will be lost.In theory, work output might be equal to work input; that would be 100% efficiency. In practice, the output of a machine will be less than the input; i.e., some energy will be lost.
25
Efficiency as a percent is output/input * 100%12000/15000 * 100% = 80% efficiency which makes sense, because it takes more work (input) than it give out (output). So the efficiency should be less than 100%.
It is output/input x 100, i.e. 60%.
output divided by input times 100 equals effiency. i.e.: 200 J of input energy and 10 J output energy calculates: 10/200 x 100%= 5%
50
Efficiency = (output/input) x 100 = (80/320) x 100 = 25%
The data goes to the printer so it is an output device.
Efficiency = ( useful energy output / total energy input ) x 100
is an omr and input or output device?