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Yes. If a uniform, homogeneous conductor is reduced to half of its length, then its conductancebecomes double, (equivalent to its resistance becoming 1/2 as great).
If half of its length is increased by 2%, then its entire length is increased by 1%.In order to know how this affects the wire's resistance, we'd want to be able toassume that its composition and cross-section are constant along its length. Thiscould be a risky assumption, especially since the length was increased ... possiblyby stretching the wire, which would certainly affect the cross section.But without overthinking the situation and making myself nervous about it, lets justassume uniform composition and cross-section along the entire length, throughoutthe observation period. Then its resistance also increases by 1%.
If the speed of a moving body is reduced to half, its kinetic eneergy is reduced to 1/4 .
Its resistance would be half , 0.5 ohms is the answer.
One-half the deep-water wave length.
Yes. If a uniform, homogeneous conductor is reduced to half of its length, then its conductancebecomes double, (equivalent to its resistance becoming 1/2 as great).
the power will be reduced to the haflf because P=V2/R so when the resistance doubles the power reduced to the half of itsoriginal value
Double the area means half the resistance. Resistance = resistivity times length / area. Resistivity is a property of the material only.
24 hours
Shorter: less resistance in proportion, so 1/2 length, half resistance, 1/3 length, 1/3 resisttance, etc. Thicker, less resistance in inverse-squared proportion, (it's the *area* that influences resistance), so 2 x diameter, 1/4 resistance, 3 x diamater, 1/9 resistance, etc. Try this: 1/2 length, 3 x diameter, gives 1/2 x 1/9 = 1/18 the resistance.
The radius is also reduced by half
If half of its length is increased by 2%, then its entire length is increased by 1%.In order to know how this affects the wire's resistance, we'd want to be able toassume that its composition and cross-section are constant along its length. Thiscould be a risky assumption, especially since the length was increased ... possiblyby stretching the wire, which would certainly affect the cross section.But without overthinking the situation and making myself nervous about it, lets justassume uniform composition and cross-section along the entire length, throughoutthe observation period. Then its resistance also increases by 1%.
Because by increasing the load resistance, the total circuit resistance is reduced. This means with less resistance, there is more current drawn from the source. Doubling the size of a load resistor increases the load current.
It cannot be reduced.
If you reduced the volume by 0.25 then the answer is evident. Your question is very vague... If you reduced the length of one side to 3/4 it's origional... volume decrease to 33/43 or 27/64 (under half) This is because volume is proportional to length cubed. If you reduced the area of one side to 3/4 it's origional... volume would decrease to 33/2/43/2 (about 65% origional) This is because volume is proportional to length cubed and area is proportional to length squared.
If the speed of a moving body is reduced to half, its kinetic eneergy is reduced to 1/4 .
It depends on the year. Up through 1919, it was sterling silver (92.5% silver), then in 1920 it was reduced to 50/50 silver and copper, and changed again in 1947 to a blend of copper and nickel, with all silver removed.