true
If the graph is a two-dimensional plane and you are graphing an inequality, the "greater than or equal to" part will be shown by two things: (1) a solid, not a dotted, line--this part signifies the "or equal to" option--and (2) which region you shade. Shade the region that contains the points that make the inequality true. By shading that region, you are demonstrating the "greater than" part.
No answer is possible. As soon as you have one valid line, all points that are not on that line cannot be part of the solution set. Therefore the solution set cannot be all real numbers.No answer is possible. As soon as you have one valid line, all points that are not on that line cannot be part of the solution set. Therefore the solution set cannot be all real numbers.No answer is possible. As soon as you have one valid line, all points that are not on that line cannot be part of the solution set. Therefore the solution set cannot be all real numbers.No answer is possible. As soon as you have one valid line, all points that are not on that line cannot be part of the solution set. Therefore the solution set cannot be all real numbers.
You draw the graph of the straight line x + 2y = 5.Evaluate the inequality at the origin: 0 + 2*0 > 5 or 0>5. This is not true so the part of the plane NOT containing the origin (above and to the right of the line) is the valid region.Also, since it is a strict equality, the line itself is not part of the valid region.
It means that the value represented by the circle is part of the solution set.
First plot 0.6 on a number line between 0 and 1,as its a decimal part...then think f0r 0.66 it ll lie between 0.6 and 0.7
It should be true, but hey you're the one who's unsure -AD
I will guess that what you refer to as a "shadow graph" serves as a way to visually represent all the answers, or solutions, to a linear inequality. For instance, if you graph y=x (a linear equality), you get the diagonal line through the origin heading 45 degrees up and to the right in one direction and down and to the left in the other. Any point on that line is a solution, even extended beyond the visible graph in both directions, "forever". However, if you graph y
If I understand the question correctly, the inequality is not strict. This means that points on the line are part of the solution and so the line is shown as a solid line rather than a dashed line.If I understand the question correctly, the inequality is not strict. This means that points on the line are part of the solution and so the line is shown as a solid line rather than a dashed line.If I understand the question correctly, the inequality is not strict. This means that points on the line are part of the solution and so the line is shown as a solid line rather than a dashed line.If I understand the question correctly, the inequality is not strict. This means that points on the line are part of the solution and so the line is shown as a solid line rather than a dashed line.
A cluster in a line graph is the major part of the line graph that connects to the plot.
The solid part of a solution is called a solute.
The solid part of a solution is called a solute.
The solid part of a solution is called a solute.
The solid part of a solution is called a solute.
Vertical line. If you can draw a vertical line through some part of a graph and it will intersect with the graph twice, the graph isn't a function.
It is the legend or key.
The Feasible Region
there is a line and ploting point