0
If the mass at the top of the plane is initially at a height of above the horizontal plane what is the velocity of m after the collision?
Wiki User
∙ 14y agoWant this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
Which is the total velocity of a projectile at maximum height?
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
What is the magnitude of the velocity of a vertical projectile at its maximum height is equal to?
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
An aeroplane flying at a constant velocity releases a bomb. As the bomb drops down from the aeroplane what will be the position of the bomb with respect to the plane?
There are two forces on the bomb when it is dropped; horizontal, and vertical. The vertical force is gravity, and the horizontal force is the velocity of the plane when the bomb is dropped. In order to determine how far away the bomb will drop from the initial point of release, it is necessary to know the height that the plane is at, and the velocity of the plane, which is also the initial horizontal velocity of the bomb (it is constant, neglecting air resistence.)
As a projectile shot at an upward angle rises and falls what happens to its horizontal component of its velocity if you neglect air resistance?
If there wouldn't be air resistance and gravity is the only thing that is effecting the projectile, the projectile will start to fall but it horizontal velocity will remain the same. So it would slow down, it would only change height.
What do you you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
Which is the total velocity of a projectile at maximum height?
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
What is the magnitude of the velocity of a vertical projectile at its maximum height is equal to?
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
An aeroplane flying at a constant velocity releases a bomb. As the bomb drops down from the aeroplane what will be the position of the bomb with respect to the plane?
There are two forces on the bomb when it is dropped; horizontal, and vertical. The vertical force is gravity, and the horizontal force is the velocity of the plane when the bomb is dropped. In order to determine how far away the bomb will drop from the initial point of release, it is necessary to know the height that the plane is at, and the velocity of the plane, which is also the initial horizontal velocity of the bomb (it is constant, neglecting air resistence.)
Calculate distance from a velocity time graph?
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
A stone is projected with a velocity of 58.8 ms at an angle of 30 degree from horizontal find the Time of flight maximum height and horizontal range?
A stone is thrown with an angle of 530 to the horizontal with an initial velocity of 20 m/s, assume g=10 m/s2. Calculate: a) The time it will stay in the air? b) How far will the stone travel before it hits the ground (the range)? c) What will be the maximum height the stone will reach?
How do you find the height of the volume of horizontal cylinder?
The height of a horizontal cylinder is 2 times its radius.
As a projectile shot at an upward angle rises and falls what happens to its horizontal component of its velocity if you neglect air resistance?
If there wouldn't be air resistance and gravity is the only thing that is effecting the projectile, the projectile will start to fall but it horizontal velocity will remain the same. So it would slow down, it would only change height.
All objects change velocity as they move toward earth at a rate of 9.8m s due to which factor of gravity?
Its 9.8 m/s2. Gravity is a force. The object starts falling on the earth's surface initially increasing its velocity but at some point the velocity becomes constant. Newton's third law can be applied to explain this. The force of gravity initially exceeds the buoyancy of air and that is when the body's fall is accelerated. But at some height the 2 forces equalize. Then the body falls at a constant velocity and this is called the drag velocity.
A ball of mass m rolls off a cliff of height h with a horizontal velocity v it reaches the ground with vertical speed of?
If one assumes air resistance to be negligible, then: final velocity = sqrt( g * 2 * h ) where g is 9.8 metres per second per second. The quantities v and m do not matter, because gravitational acceleration does not depend on mass (all objects fall at the same rate) and because the horizontal velocity is independent of the vertical velocity.
