Depending on the reaction, may be reactant or product.
The products are salt and water.
NaOH + HCl = NaCl + H2O
CH3COONa, CO2 and H2O
ch3ch(oh)ch2cn
NaOH and HCl are the reactants; water and ammonium chloride are the products.
First, its HCl, with a lowercase L, not HCI. The reaction is HCl + NaOH --> H2O + NaCl
NaOH + HCl --> NaCl + H2OWith the reaction of a strong base and a strong acid, a neutralization reaction, one sees a salt, sodium chloride here, and water.
An acid-base reaction
The product will contain only Zn, H, and CI. -Apex
NaCl
NaOH and HCl are the reactants; water and ammonium chloride are the products.
The product of this reaction is salt:NaOH + HCl = NaCl + H2O
First, its HCl, with a lowercase L, not HCI. The reaction is HCl + NaOH --> H2O + NaCl
NaOH + HCl --> NaCl + H2OWith the reaction of a strong base and a strong acid, a neutralization reaction, one sees a salt, sodium chloride here, and water.
An acid-base reaction
NaCl and H2O
The product will contain only Zn, H, and CI. -Apex
The reaction is:NaOH + HCl = NaCl + H2O
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
This equation is Na2CO3 + 2 HCl -> 2 NaCl + CO2 (gas) + H2O.
This neutralization reaction is:NaOH + HCl = NaCl + H2O