Acceleration is a change in speed or direction of motion. You
haven't said anything about changes of speed or direction.
Any measure of length, such as meters, centimeters, or light-years.
Any unit of length: millimeter, meter, kilometer, light-year, etc.
The speed of light in vacuum is a universal constant. The distance around the earth depends on the line of measurement. Because of its rotation, the earth is not a perfect sphere: its equatorial radius is 0.3% greater than its polar radius. Consequently the measurement is affected by the exact line along which the radius is measured. Furthermore, there are two kinds of variations in the equatorial radius. One is a long-term variation caused by the distribution of mass on the surface: possibly the ocean mass. There is also the short term variation caused by the gravitational pull of the moon.
The schwarzschild radius of the Earth is about 8.7 x 10 to the negative 3m. The schwarzschild radius is the radis of a sphere that is around a non-rotating blackhole. You find the Rs, or radis, by multiplying the gravitational constant(G), the mass(M), and two. You divide this by the speed of light(c) squared.
Tides, length of the day, variable light at night (for hunting).
You would feel heavier. The acceleration due to gravity on Uranus is 10.72, while the acceleration due to gravity of Earth is 9.8 m/s2 (or 9.81, it depends on who you ask.).
It is approximately 75,000 light years in radius
Speed of light = 186,282 miles per second.500 seconds at this speed = (500 x 186,282) = 93,141,000 miles
The speed of light is a constant, so the acceleration is zero. However, light IS affected by gravity, and gravity causes an acceleration. How does this balance? The light moves at the same speed - the speed of light, abbreviated "c" - but loses or gains energy as the light moves toward or away from the gravity source. In gaining energy (without speeding up!) the frequency of the light is increased and the wavelength of the light (or any electromagnetic energy) is decreased, In losing energy, the wavelength is increased and the wavelength decreased. This could be a trick question, of course. Light from a star wouldn't be travelling from earth, unless we are talking about reflected light, which would not be particularly intense, but it is not out of the question.
By unit of length and distance and conversion ,we can say that the distance from Earth to sun is calculated with the help of light years.
radius of curvature is double of focal length. therefore, the formula is: 1/f = (n-1)[ 1/R1 - 1/R2 + (n-1)d/nR1R2] here f= focal length n=refractive index R1=radius of curvature of first surface R2=radius of curvature of 2nd surface d=thickness of the lens using this, if you know rest all except one, then you can calculate that.
Regulus is 77.5 light-years away from our solar system. (The diameter of Earth's orbital radius is 16 light-MINUTES, so our orbit around the Sun doesn't make any significant difference.)