(2x - 1) + (2x + 1) = 52
4x = 52
x = 13
The first 2 of 5 consecutive odd integers are 25 and 27.
(Check: 25 + 27 = 52 yay!)
The last 2 of 5 are 31 and 33.
Their sum is 64.
Let the first odd integer be x, then the second one is x + 2. So we have: x + (x + 2) = 52 2x + 2 = 52 subtract 2 to both sides 2x = 50 divide by 2 to both sides x = 25 Thus, the first number is 25. Since consecutive odd integers grow by 2, then the second is 27, the third is 29, the fourth is 31, and the fifth integer is 33. So the sum of the last two integers is 64 ( 31 + 33).
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
You can always guess and check! When they are consecutive, it means they must be the next odd integer up from the last. For this, it is 11, 13, 15. 11+13+15= 39
They are 13.
1 x 10 x 10 x 10 x 9 = 9000 1 = it must be 2 10's = any digits 9 = any digit BUT zero
Let the first odd integer be x, then the second one is x + 2. So we have: x + (x + 2) = 52 2x + 2 = 52 subtract 2 to both sides 2x = 50 divide by 2 to both sides x = 25 Thus, the first number is 25. Since consecutive odd integers grow by 2, then the second is 27, the third is 29, the fourth is 31, and the fifth integer is 33. So the sum of the last two integers is 64 ( 31 + 33).
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
The integers are: x, x+1, and x+2.x2 + (x+2) = 8x2 + x - 6 = 0(x - 2) (x + 3) = 0x = + 2x = - 3Two solutions:=> The integers are 2, 3, and 4=> The integers are -3, -2, and -1
14, 16, 18 and 16, 18, 20
The sum of 50 consecutive odd integers is equal to: (First Term + Last Term) * (The number of Terms)/2 or in this case, more specifically: (2 * First Term + 98) * 25 If you meant 1+3+5+7+...+99, then the sum is 2500.
Start from the last integer. Subtract 2 from it, to get the second-last. Subtract 2 from that one, to get the third-last, etc.
You can always guess and check! When they are consecutive, it means they must be the next odd integer up from the last. For this, it is 11, 13, 15. 11+13+15= 39
consecutive order or chronological order
16,17,18,19,20,21,22,23,24,25.
The three integers are ±13, ±15, and ±17. The difference between ±132 and ±172 is equal to 289 - 169 = 120.
1994
(First + last) multiplied by half the last, in this case 31 x 15 ie 465.