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Answered 2008-05-05 15:01:47

2.75 m/s

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The velocity of a body was noted to be constant during five minutes of its motion What was its acceleration during this interval?

Acceleration means speeding up or slowing down, a change in velocity. Since the velocity was constant, the acceleration was. 0


What are three components needed to find an object acceleration?

Using the definition of acceleration as change of speed / time, you basically need to know: * A time interval during which the object accelerates. * The velocity at the beginning of this time interval. * The velocity at the end of this time interval.


Does time equals velocity over acceleration?

Yes, sort of. At least, that's the units used. The actual definition of acceleration is: a = dv/dt In other words, the rate at which velocity changes. In the case of constant acceleration, that would be equal to a change in velocity, divided by the time interval during which this change takes place. In the case of non-constant acceleration, the acceleration, or rate of change of velocity, can of course change from one moment to another.


An increase of speed during a given interval of time is called?

The shift of velocity per unit of given time is called acceleration. The types of acceleration are negative acceleration and positive acceleration.


If the velocity of an object changes from 65msto 98ms during a time interval of 12s what is the acceleration of the object?

Average acceleration is a net change in velocity over a corresponding change in time.Your velocity went from 65 to 98 m/s - that's a positive change (gain) of 33 m/s.the time interval was 12 s.+ 33/12 m/s/s = + 2.75 m/s/s.


Which physical quantity changes continually during a uniform circular path?

The position, the velocity, and the acceleration.


Is it true that you find acceleration when initial velocity final velocity and time are given?

With that information, you can find the average magnitudeof the accelerationduring that period of time. You can't tell what either the magnitude or directionwere at any time during, only the average magnitude for the whole interval.


If the speed of an object changes from 121ms to 98ms during a time interval of 12 s what is the acceleration of the object?

We have this equation: Velocity after = Initial velocity + (acceleration * time) So, let's plug in the numbers into this equation. 98m/s = 121m/s + (acceleration * 12seconds) So, -23 = 12 seconds * acceleration dividing 12 from both sides, the acc. is -1.92m/s/s. (Yes, those are the UNITs of acceleration. And it's negative because the object slows down. )


How is acceleration calcuated?

Dividing change of velocity by the time it takes to change the velocity. If acceleration is not constant, this will give you the average acceleration during the period; to get the instantaneous acceleration, you have to take the derivative of the velocity.


A skydiver steps from a helicopter and falls for 5 seconds before reaching her terminal velocity during this 5 second interval her acceleration?

the crate will reach terminal velocity last, but hit the ground frist.


What is an increase of speed during a given interval of time?

Acceleration. Deceleration is a decrease of speed during a given interval of time.


A skydiver steps from a helicopter and falls for 5 seconds before reaching her terminal velocity During this 5 second interval her acceleration will?

increase- your speed will increase until terminal velocity is reached. From there it will stay constant.


What increases speed during a given interval of time?

acceleration


Which is an increase of speed during a given interval of time?

"acceleration"


If the speed of an object changes from 121 meters per second to 98 meters per second during a time interval of 12 seconds what is the acceleration of the object?

Acceleration = change in velocity/time a = (v - u) /t where a= acceleration, v= velocity, u= initial velocity & t= time. u = 121 m/s v = 98 m/s t = 12 m/s a = (98 - 121) /12 a = -23/12 a = -1.91667 m/s2


If the speed of an object changes from 121ms to 98 ms during a time interval of 12s what is the acceleration of the object?

Acceleration is equal to the change in velocity over the change in time [a=(vf-vi)/(tf-ti). a=(98m/s - 121 m/s)/(12s)=(-23m/s)/(12s)=-1.92m/s^2


If the speed of an object changes from 121 ms to 98 ms during a time interval of 12s what is the acceleration of the object?

Average acceleration during the time interval = (change on speed) / (time for the change) =(98 - 121) / (12) = -23/12 = negative (1 and 11/12) meters per second2


If the speed of an object changes from 121 m's to 98 m's during a time interval of 12 s what is the acceleration of the object?

-1.9166... m/s2


If the speed of an object changes from 121 ms to 98 ms during a time interval of 12 s what is the acceleration of the object?

-1.92 m/s2


What id an instantaneous accelaration mean?

It means acceleration at a specific instant of time. You can calculate the average acceleration by dividing change of velocity, by the time during which this changes. If you take smaller and smaller times, dividing change of velocity by a small time interval in every case, you can imagine approaching the "true" acceleration.


Which of these is an increase of speed during a given interval of time?

positive acceleration


How to find acceleration?

Acceleration has two parts ... its size and its direction.To find the size (magnitude):-- pick a time interval-- measure the speed at the beginning of the interval-- measure the speed at the end of the interval-- subtract the speed at the beginning from the speed at the end-- divide that difference by the length of the time interval-- the result is the magnitude of acceleration during that time interval


If the velocity is zero for a time interval is the accelaration zero at any instant within the time interval?

Yes, but only if the instantaneous velocity remains zero during the time inerval. If you are speaking of average velocity over an interval, all bets are off.


What is the value of acceleration for a body?

Acceleration means how fast the body's velocity changes - in symbols, dv/dt. Average acceleration during a certain time is equal to (change in velocity) / (time elapsed). Since you are dividing a velocity by a time, the standard unit for acceleration is (meters / second) / second, but this is normally written as meters / second squared.


If a train is stopped suddenly then it's acceleration will be zero or it's velocity will be zero?

As it slows it's acceleration will be negative, deceleration is negative acceleration. During the slow down the velocity will drop. Once at rest both acceleration and velocity will be zero.