0
If the velocity of an object changes from 65 ms to 98 ms during a time interval of 12 s what is the acceleration of the object?
Wiki User
∙ 16y ago
2.75 m/s
Wiki User
∙ 16y ago
Add your answer:
Earn +20 pts
What is the value of acceleration for a body?
Acceleration means how fast the body's velocity changes - in symbols, dv/dt. Average acceleration during a certain time is equal to (change in velocity) / (time elapsed). Since you are dividing a velocity by a time, the standard unit for acceleration is (meters / second) / second, but this is normally written as meters / second squared.
What must you calculate to determine the acceleration of an object?
You must calculate the change in velocity during each unit of time.
A construction truck collides with the back of a subcompact car Which one has the larger change of velocity during the collision?
The smaller vehicle will encounter the larger velocity change.
A car starts from rest with a constant acceleration of 5 ms2 How much time does the car take to cover the first 160 m?
To solve this you need the basic equations connecting velocity, acceleration, distance, and time. If the acceleration or deceleration is uniform (ie constant over the time interval), these can be expressed as: (1) a = (v - u)/t (2) s = u x t + 1/2 x a x (t squared) (3) (vsquared) = (usquared) + (2a x s) where a = acceleration, v = final velocity, u = initial velocity, s = distance, t = time, take it in three parts: 1. Acceleration from rest, u = 0, v = 50, a = 10. So from equation (3) s = vsquared/2a = 2500/20 = 125m. Equation (2) gives the same result. 2. Uniform speed at 50 m/sec for 2 sec, s = 100m 3. Deceleration in 3 sec, starting at 50m/sec and ending at zero, from (1) a = 50/3 = 16.67 m/sec/sec. So from equation (2), s = 50 x 3 + 1/2 x 16.67 x 9 = 75m. Equation (3) gives the same result. ( It's worth checking this!) So total distance = 125 + 100 +75 = 300 meters. I've spent a bit of time on this, to show you how to do it rather than just give you the answer. Try to memorise these equations, or at least write them down in a notebook and try to understand what is happening at each stage. Always break such a problem down into different stages of acceleration or braking. This will be useful if you become an engineer ( or even a rocket scientist).
Is it possible that an object moving in certain direction with an accleration in the perpendicular direction?
yes. this is the baseline understanding for rotational motion. Think of driving a car, if you turn the wheel of the car then you are directing the frictional force near perpendicular to your velocity and thus "turn" the car. More precisely, the car's acceleration is radial while its velocity is tangential and thus the car is following a rotational path, during the turning phase of travel.
The velocity of a body was noted to be constant during five minutes of its motion What was its acceleration during this interval?
Acceleration means speeding up or slowing down, a change in velocity. Since the velocity was constant, the acceleration was. 0
Is the velocity of an object changes from 65 ms to 98 ms during a time interval of 12 s what is the acceleration of the object?
2.75 m/s
What are three components needed to find an object acceleration?
Using the definition of acceleration as change of speed / time, you basically need to know: * A time interval during which the object accelerates. * The velocity at the beginning of this time interval. * The velocity at the end of this time interval.
Does velocity equal acceleration x time?
Yes, sort of. At least, that's the units used. The actual definition of acceleration is: a = dv/dt In other words, the rate at which velocity changes. In the case of constant acceleration, that would be equal to a change in velocity, divided by the time interval during which this change takes place. In the case of non-constant acceleration, the acceleration, or rate of change of velocity, can of course change from one moment to another.
An increase of speed during a given interval of time is called?
The shift of velocity per unit of given time is called acceleration. The types of acceleration are negative acceleration and positive acceleration.
Which physical quantity changes continually during a uniform circular path?
The position, the velocity, and the acceleration.
If the speed of an object changes from 121ms to 98ms during a time interval of 12 s what is the acceleration of the object?
We have this equation: Velocity after = Initial velocity + (acceleration * time) So, let's plug in the numbers into this equation. 98m/s = 121m/s + (acceleration * 12seconds) So, -23 = 12 seconds * acceleration dividing 12 from both sides, the acc. is -1.92m/s/s. (Yes, those are the UNITs of acceleration. And it's negative because the object slows down. )
A skydiver steps from a helicopter and falls for 5 seconds before reaching her terminal velocity during this 5 second interval her acceleration?
the crate will reach terminal velocity last, but hit the ground frist.
If the speed of an object changes from 121 meters per second to 98 meters per second during a time interval of 12 seconds what is the acceleration of the object?
Acceleration = change in velocity/time a = (v - u) /t where a= acceleration, v= velocity, u= initial velocity & t= time. u = 121 m/s v = 98 m/s t = 12 m/s a = (98 - 121) /12 a = -23/12 a = -1.91667 m/s2
A skydiver steps from a helicopter and falls for 5 seconds before reaching her terminal velocity During this 5 second interval her acceleration will?
increase- your speed will increase until terminal velocity is reached. From there it will stay constant.
If the speed of an object changes from 121ms to 98 ms during a time interval of 12s what is the acceleration of the object?
Acceleration is equal to the change in velocity over the change in time [a=(vf-vi)/(tf-ti). a=(98m/s - 121 m/s)/(12s)=(-23m/s)/(12s)=-1.92m/s^2
How is acceleration calcuated?
Dividing change of velocity by the time it takes to change the velocity. If acceleration is not constant, this will give you the average acceleration during the period; to get the instantaneous acceleration, you have to take the derivative of the velocity.
