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A car starts from rest with a constant acceleration of 5 ms2 How much time does the car take to cover the first 160 m?
Wiki User
∙ 14y ago
To solve this you need the basic equations connecting velocity, acceleration, distance, and time. If the acceleration or deceleration is uniform (ie constant over the time interval), these can be expressed as:
(1) a = (v - u)/t (2) s = u x t + 1/2 x a x (t squared) (3) (vsquared) = (usquared) + (2a x s)
where a = acceleration, v = final velocity, u = initial velocity, s = distance, t = time,
take it in three parts:
1. Acceleration from rest, u = 0, v = 50, a = 10. So from equation (3) s = vsquared/2a = 2500/20 = 125m. Equation (2) gives the same result.
2. Uniform speed at 50 m/sec for 2 sec, s = 100m
3. Deceleration in 3 sec, starting at 50m/sec and ending at zero, from (1) a = 50/3 = 16.67 m/sec/sec. So from equation (2), s = 50 x 3 + 1/2 x 16.67 x 9 = 75m. Equation (3) gives the same result. ( It's worth checking this!)
So total distance = 125 + 100 +75 = 300 meters.
I've spent a bit of time on this, to show you how to do it rather than just give you the answer. Try to memorise these equations, or at least write them down in a notebook and try to understand what is happening at each stage. Always break such a problem down into different stages of acceleration or braking. This will be useful if you become an engineer ( or even a rocket scientist).
Wiki User
∙ 15y ago
Wiki User
∙ 14y agoThe equation that relates distance to acceleration is (1/2) *A (m/s^2) * t^2(s^2) = D (m), using that logic, (1/2) 5 m/s^2 * t^2(s^2) = 160 m. Following the math out 5 m/s^2 * t^2 = 320 ==> t^2 = 64 ==> x = 8s
Wiki User
∙ 14y agoDraw the velocity time graph for the motion of the body and answer the following questions a) what is the maximum velociety attained by the body? b) what is the distance travelled during this period of acceleration? c) what is the distance travelled when the body was moving with a constant velocity? d) what is the retardation of the body while slowing down? e) what is the distance travelled while retarding? f) what is the total distance travelled? g) what is the average velocity of the body during the entire journey?
Wiki User
∙ 14y ago1 km = 1,000 meters
1 hour = 3,600 seconds
100 km/hr = 100,000 meters / 3,600 seconds = 1,000/36 = 250/9 meters/sec
To reach this speed in 5.8 sec, acceleration = (250/9) / 5.8 = 4.789 meters/sec2 (rounded)
Wiki User
∙ 15y ago30 km - hr/ 5 sec = 1000m/1km =30000m 30000m/5 sec = 3600 sec/1hr =722 sec
Wiki User
∙ 6y agoacceleration (a) = velocity (v) divided by time (t); a = 3/10 = 0.3 m/s/s
Wiki User
∙ 7y ago1.5 meters/secound2
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