Yes it would start glowing more brightly but at a certain point it would burn ou if you go on increasing the power.
This is a perfect example of Ohm's law.
It increase by The cube of Two, namely increases by
It depends on the battery charger. Some chargers will detect that they're hooked up backwards and do nothing. More than likely though it will dis-charge the battery pretty quickly, and probably damage it.
replace the alternator
Since the stroke volume increased then the cardiac out put would increase, pumping out more blood with the same amount of heart beats.
That depends on how dead the battery is, condition of the battery, weather, etc. A good battery that hasn't dropped too far below 12.0 Volts (12.0 is officially 'dead') will continue to sulfate and increase the electrolyte levels to a certain extent. If these levels are raised high enough, your voltage will raise also. Depending on the load required to start your car, the battery may recover enough on it's own to provide you with one last start. Also, temperature plays a big part in how fast a battery sulfates. Hydrometer readings can vary greatly from a cold day to a warm day. If your battery dies at 3 AM while it's 35 degrees outside, but later it warms to a balmy 80 degrees, you certainly have a better chance. As always though, it's usually better not to let this happen in the first place. And I wouldn't want to bet on a battery's 'natural' recovery. Lead Acid batteries can be a funny animal, and no two are the same.
The brightness of three bulb would be mare than one
The brightness of a bulb would not change if you added a second bulb in parallel with the first.Unless, of course, the increased current exceeded the power supply's capacity causing a reduction in voltage.
If smaller means less power for the same voltage, then a smaller bulb would result in less brightness. If smaller means less voltage for the same power, then a smaller builb would result in more brightness.
the battery will stop working.
A: Nothing will happen if the load increases or even removed the voltage will go to the open voltage condition no harm.
Two things can happen. 1. the voltage regulator fails so that the alternator doesn't know the battery charge is dropping therefore the battery doesn't get charged. 2. The voltage regulator fails in such a way as to allow the alternator to overcharge the battery which causes the battery to overheat and fail, Sometimes an overcharged battery can explode.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
when you lick a 9 voltage battery you get a tiny shock on your toung and it hurts.
Either you won't get enough voltage, and the car will stop once your battery is discharged, or you'll get excessive voltage, and you could end up actually overloading the battery and causing it to rupture, starting a fire, etc.
Ohms Law says Voltage = Current x Resistance. Hence if voltage rises, so will current.
It will 1, not charge it at all. And 2, actually "uncharge" the battery
Nothing special should happen. What matters for the bulb is the voltage difference between its ends.