Unless the object is changing its direction, it is not accelerating. Constant velocity implies that speed and direction are constant, and for acceleration to occur, either speed, direction, or both values must be changing.
When something is traveling at a constant velocity it has no acceleration. In other words your answer is 0.
You need velocity at two points in time, and the acceleration must be constant. If the initial velocity is u ms-1 and the final velocity is v ms-1, and the time interval is t then t = (v - u)/a s.
Average acceleration = (amount of change in speed velocity) / (time for the change) = (30 - 10) / (4) = 5 meters per second2 to the east
Acceleration = (change in speed) / (change in time) = (30 m/s) / (10 sec) = 3 meters per second2
4.0 s
Acceleration is the rate of change in velocity. (Velocity is speed+direction, it is a vector as well as acceleration). F=ma, where a is in ms^(-2).
What is the only factor needed to calculate change in velocity due to acceleration of gravity 9.8 ms?
It is 0.1 metre per second-squared.
It is 0 N because it's moving at a constant velocity so the acceleration would be 0. Net Force = m x a so Net Force = 1850 kg x 0 m/s/s
acceleration=(final velocity-initial velocity) divided by t a=Δv/t a=(63.9-5.56)/7.5 a=58.34/7.5 a=7.778666667≈7.8 meters per second squared (m/s2)
It is 0.1 metre per second-squared.
It is 0.1 metre per second-squared.