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Ten-pin bowling balls usually weigh from about 6 pounds (around 2800 grams) to 16 pounds (about 7200 grams) There are no bowling balls that weigh 200 grams (though such a ball would be leagal as there is no minimum weight) but if there were, the mass of the ball divided by the volume of the ball gives the density. The volume of a standard bowling ball is about 5500 cubic centimeters (I assumed a circumference of 27 inches and calculated from that) 200 / 5500 = 0.036 g/cm3 Compare to the density of air = 0,0012 g/cm3
Used the equation Density=Mass/Volume to solve this one.
Density = mass/volume let us say the mass of the steel ball and the ship are same. but the steel ball is fully enclosed, a tight spherical volume, where as the ship is a hollow, occupies more volume (multiple times) as that of the spherical ball. Considering the first equation, u know well the density of steel ball is much higher than the steel ship.
Two small, plastic balls attached to a larger plastic ball by toothpicks
0.0125
If two perfect spheres of different sizes have the same mass, then the larger ball has a lower density and the smaller ball has a higher density. This is because density is the amount of mass in a given volume, and density is obviously higher if there is a smaller volume for a given amount of mass.
Density is mass divided by volume. If the density is greater and the volume is the same then the mass must also be greater for the same size balls.
Ten-pin bowling balls usually weigh from about 6 pounds (around 2800 grams) to 16 pounds (about 7200 grams) There are no bowling balls that weigh 200 grams (though such a ball would be leagal as there is no minimum weight) but if there were, the mass of the ball divided by the volume of the ball gives the density. The volume of a standard bowling ball is about 5500 cubic centimeters (I assumed a circumference of 27 inches and calculated from that) 200 / 5500 = 0.036 g/cm3 Compare to the density of air = 0,0012 g/cm3
The ball's volume is 0.25 L
Unless you can calculate or measure the volume, you cannot. And even if you could you would get the average density - of the material of the ball and the air inside.
Used the equation Density=Mass/Volume to solve this one.
How many balls are in one can? Three? If so, then calculate the volume of one ball and multiply by three. That's the volume occupied by the balls. The volume of a sphere is given by the formula V = 4(Pi)r3/3. Now calculate the volume of the cylinder. Assume that its height is three times the diameter of a ball (if there are three balls in the can). Remember that the diameter is twice the radius. Also, assume that the radius of the can is equal to the radius of one ball. The volume of a cylinder is given by the formula V = (Pi)r2h. Now subtract the volume of the balls from the volume of the can.
No. If the density of the item is less, the mass may be less, even if the object is larger. Cannon ball and a beach ball. Low density beach ball has far less mass than the VERY dense cannon ball, even though the beach ball is larger.
Why not ? The density is (mass) divided by (volume). As long as the answer tothe division is the same, the densities are the same.Here's a simple example:Take one brand new golf ball. It has a mass, it has a volume, and (mass) / (volume)is the density of the golf ball.Now take a carton of 24 of the same identical golf balls. The whole load of themhas 24 times as much mass as the single ball, and it also has 24 times as muchvolume as the single ball. When you divide the total mass by the total volume youget exactly the same number you got for the single ball. 24 of them all togetherhave the same density as one of them has, even though their mass is differentfrom a single ball and their volume is different too.The density doesn't depend on the mass or the volume. It only depends on theanswer to the division of one by the other. That's why it's such a useful number.It totally does not depend on the size of the sample. The density of golf ballscan be directly and precisely compared to the density of dust particles, boulders,battleships, and asteroids.
because a small ball has more density
There are several methods that can be used to calculate the density of a metal ball. The density of a metal ball can be derived from the fact that the volume is: 4*(pi)*r^3/3 and the denisty is mass/volume. If the mass and moment of inertia are known but the dimensions of the metal ball are not, then you can use the fact that the moment of inertia of the ball is 2m*r^2/5 and solve for m to get r=(5I/2)^.5 and plug in the value for r into the volume equation then calculate the density of the ball by dividing the mass by the calculated volume.
In almost all cases it is impossible. If the ball is solid and made from uniform material - a "dog ball" is the only example that comes to mind - then, if the density of the material is known, the volume can be calculated using Volume = Mass*DensityHaving obtained the volume, r^3 = 3V/(4*pi) where r is the radius.then r = cube root of 3V/(4*pi)Normally balls are hollow and so the assumption about uniform density is not appropriate. Therefore you cannot estimate the volume of the material in the ball. And even if it were, you could not distinguish between a small ball with a thick outer layer or a large ball with a thin skin.