As altitude increases (to about 35,000 ft) air density, pressure and temperature all drop.
As density decreases speed of sound increases, but with drop in pressure it drops; these two practically cancel each other out.
As temperature drops, speed of sound drops.
Thus at 15,000 ft the speed of sound is slower than at 6,000 ft so plane X is flying faster than plane Y.
No. plane X will be faster. because, the speed of sound is not a constant. it depends on the altitude. for example, the speed of sound (mach1)at sea level is about 1221km/h and the speed of sound at 30000ft is about 1091km/h. that is, the speed of sound is reduced with higher altitudes. so the plane X which is at lower altitude travels faster because the speed of sound is faster at that altitude.
I believe the air at a higher altitude would usually be colder in this case; this would make the speed of sound slower at the higher altitude.
plane y flying faster
plane y for a+ users
Plane Y
H2O NaCl
15kg is 15000g. 15000/58.12 = 258.087 moles.
2,500
1,500 milligrams, since each gram is 1,000 milligrams.
Assume the car gets 30 miles per gallon of octane burned.Voct = 15000 mi / 30 mi/gal = 500 galmoct = Voct / doct = ( 500 gal ) / ( 6.0 lbm / gal ) = 83.33 lbm octanenoct = moct / Moct = ( 83.33 lbm ) / ( 114.29 lbm/lbmol ) = 0.7291 lbmolnCO2 = ( 0.7291 lbmol C8H18 ) ( 8 mol CO2 / mol C8H18 ) = 5.833 lbmol CO2nCO2 = ( 5.833 lbmol CO2 ) ( 453.6 gmol CO2 / lbmol CO2 ) = 2646 gmol CO2VCO2 = ( nCO2 ) ( R ) ( T ) / ( P )VCO2 = ( 2646 mol ) ( 0.08206 atm - L / gmol - K ) ( 298.2 K ) / ( 1.01 atm )VCO2 = 64100 L at 25 C and 102 kPa
The higher up in the atmosphere you are, the thinner the air and therefore the less the drag on the plane. Thus if both planes' engines are under the same power (using the same amount of fuel) the plane at the higher altitude will have a faster airspeed.
At about 30,000 feet, the air is thinner and the aircraft has little resistance at that height, because of that little resistance the plane can fly much further
Flying? Sydney, Australia.
15000 = 15000/1
19% of 15000= 19% * 15000= 0.19 * 15000= 2850
110% of 15000= 110% * 15000= 1.1 * 15000= 16,500
750.5% of 15000= 0.5% * 15000= 0.005 * 15000= 75
30% of 15000 = 30% * 15000 = 0.3 * 15000 = 4500
17% of 15000 = 17% * 15000 = 0.17 * 15000 = 2550
1% of 15000 = 1% * 15000 = 0.01 * 15000 = 150
Each 1000ft of ascent will bring a cooling of about 3 degrees Centigrade, so at 15000 feet the temperature would have fallen by 45 Centigrade degrees. That seems a lot but that was our basic guide in wartime when we learned to fly. If the cockpit canopy didn't close too well your nose would suffer unless it was inside your flying mask.
Numbness will last till the decreased oxygen returns to normal levels in the body. (PAO2)