to p or not to p that is the question, take the p out of it and the question is the answer!
It's x = 0. Consider a point of the plane, P=(x, y), in cartesian coordinates. If P is a point belonging to x-axis, then P=(x, y=0); if P is a point belonging to y-axis, then P=(x=0, y).
Suppose you are given a side X unit and perimeter P units of length.Suppose the other pair of sides are Y units long.Then P = 2*(X+Y) so that Y = (P-2X)/2 or (P/2 - X) units.And so, the area = X*Y = X*(P/2 - X) or XP/2 - X2square units.Suppose you are given a side X unit and perimeter P units of length.Suppose the other pair of sides are Y units long.Then P = 2*(X+Y) so that Y = (P-2X)/2 or (P/2 - X) units.And so, the area = X*Y = X*(P/2 - X) or XP/2 - X2square units.Suppose you are given a side X unit and perimeter P units of length.Suppose the other pair of sides are Y units long.Then P = 2*(X+Y) so that Y = (P-2X)/2 or (P/2 - X) units.And so, the area = X*Y = X*(P/2 - X) or XP/2 - X2square units.Suppose you are given a side X unit and perimeter P units of length.Suppose the other pair of sides are Y units long.Then P = 2*(X+Y) so that Y = (P-2X)/2 or (P/2 - X) units.And so, the area = X*Y = X*(P/2 - X) or XP/2 - X2square units.
(i) P(X <= 2, Y = 1) = P(X=0, Y=1) + P(X=1, Y=1) + P(X=2, Y=1) = (0+1)/30 + (1+1)/30 + (2+1)/30 = 6/30 = 1/5. (ii) P(X + Y = 4) = P(X=2, Y=2) + P(X=3, Y=1) = (2+2)/30 + (3+1)/30 = 8/30 = 4/15.
Any F(x) = P(x) + b, where b = 0 and P(x) can be factored by x. Ex) y = 843x y = x^32 + x^23 + 4x
p(x) = x4 + 2x3 + x2 + 8x - 12When you go to graph this function, you make 'y' = p(x) .At the y-intercept, 'x' is zero.There, y = -12 .
If X and Y are i.i.d Poisson variables with lambda1 and lambda2 then, P (X = x | X + Y = n) ~ Bin(n, p) where p = lambda1 / lambda1 + lambda2
Let X and Y be two random variables.Case (1) - Discrete CaseIf P(X = x) denotes the probability that the random variable X takes the value x, then the joint probability of X and Y is P(X = x and Y = y).Case (2) - Continuous CaseIf P(a < X < b) is the probability of the random variable X taking a value in the real interval (a, b), then the joint probability of X and Y is P(a < X< b and c < Y < d).Basically joint probability is the probability of two events happening (or not).
If x is one of the numbers and y the other, then their sum is x+y = 53. So y = 53-x where x>0 and y>0 implying that x<53. Then, their product, P = x*y = x*(53-x) = 53*x - x2 for 0<x<53 [P is not defined for other values of x]
P-orbitals have dumbbell shape.their X & Y orientation is same as the X & Y coordinate axis and that of Z is represented making 45 degree to X and Y
If we assume a 2D topography with XX and YY axes, we can write any two points on that surface as p(x,y) and P(X,Y) where x, X, y, and Y are the coordinates of each point. So the distance between p and P is S = sqrt(Sx^2 + Sy^2) where Sx = X - x and Sy = Y - y. EX: Assume p(2,4) and P(4,9); then we have S = sqrt((4 - 2)^2 + (9 - 4)^2) = 5.39 units. ANS.
Suppose that for any pair of numbers x and y, gcf(x, y) = g then x = g*p and y = g*q for some integers p and q. Therefore x + y = g*p + g*q = g*(p+q).
If (p, q) is any point on the line, then the point slope equation is: (y - q)/(x - p) = 2 or (y - q) = 2*(x - p)