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possible mendelian ratios for monohybrid cross genotype is 1:2:1 and phenotype is 3:1
you can chage the state
9:3:3:1 ratio of dihybrid cross
Wow, many different aspects to look at here. One big one is if it is in every generation or not. If so, then you have a dominant mutation that will show in every individual with an allele for that gene. If it seems to skip generations then you have a recessive mutation. Basically to answer this question you need to look at your family tree and determine what is going on and if every generation has it, they will have it. If your generation has it, they won't.
you should expect maybe cold weather in the Himalayas.
If one trait is dominant over the other, then the resulting F1 generation would be expected to have the heterozygous genotype and dominant phenotype.
possible mendelian ratios for monohybrid cross genotype is 1:2:1 and phenotype is 3:1
Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.
They perform a test cross. A test cross takes the unknown genotype and crosses it with a known homozygous recessive. If the F1 generation is all dominant, then they know the organism was a homozygous recessive. If recessive offspring appear, then the organism was a heterozygote. As an example, consider a gene with two alleles, A and a, with Adominant. Now consider the test cross. The unknown genotype can only be one of two possibilities: AA (homozgous dominant) Aa (heterozygous) In a test cross,the unknown genotype is crossed with a known homozygous recessive. Since there are only two possible unknown genotypes, there can be only two possible results. First, consider the case of the unknown genotype being a homozygous dominant. The cross looks like this: AA X aa Remember that a homozygote for an allele can only produce one kind of gamete. In this case the homozygous dominant can only produce gametes with the allele A in them, while the homozygous recessive can only produce gametes with the recessive allele a in them. This means the F1 offspring can only be ONE genotype; Aa. Therefore, all of the offspring would have the dominant phenotype. Now consider the other possible cross, where the unknown genotype is heterozygous: AaX aa Remember that a heterozygote can produce two types of gametes. In this case, the unknown would produce gametes with the dominant allele A or the recessive allele a. The homozygous recessive would still only produce one kind gamete, with the recessive a allele. Therefore, we expect to see only two genotypes in the F1, Aa and aa, in equal proportions. In either case, only one test cross is needed to tell one immediately the nature of the unknown genotype. If all of the F1 are of the dominant phenotype, then the unknown genotype must be homozygous dominant; if a mixture of phenotypes appears in equal proportion, then the unknown genotype must be a heterozygote.
Natural selection acts solely on phenotype. However, the probability of certain genotypes can be affected by the probability of a certain phenotype surviving. For example, say all the hawks eat all the dark mice and the dark allele for skin color is dominant (D). The hawk doesn't care whether the dark mice is Dd or DD, they will eat them either way and in the same proportions. This affects the genotypes of the populations because in this case, genotypes of DD and Dd will become less frequent than dd.
Yes, we expect the sixth generation in the spring of 2015. Start saving today!
First. Expect another 5 months.
You will have to expect morning sickness, the mood swings to kick in, the fact that you will start to experience cravings is another thing to expect.
You would expect 1 homozygous dominant, 2 heterozygous dominant and 1 homozygous recessive offspring. This is because each parent has one dominant and one recessive allele. Therefore there is a 75% chance of a dominant phenotype and a 25% chance of a recessive phenotype.
i do we have a lot of harsh winters her in saskatchewan
To search, seek, expect, hunt.
you can chage the state