it would quadruple (become 4 times as big)
The relation between the height of a triangle, its base and its area is given by: Area = 0.5 * Base * Height Therefore, we have: Height = (2 * Area)/ Base.
The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.
The area of a triangle is (1/2) x (length of the base) x (height of the triangle). You ought to be able to handle it from this point.
the height of a triangle is three feet longer than the base. The area of the triangle is 35 square feet. Find the height andbase of the triangle
Area of a triangle = (1/2) x (base) x (height) Can you handle it from there ?
The area of the triangle would double
The area doubles if the base stays the same.
If you only have the triangle's area, then you only know the product of (base times height) ... it's double the area ... but you can't tell what either of those individual lengths is.
The area gets doubled.
Doubling the base of a triangle while keeping the height constant will double the area of the triangle. The area of a triangle is directly proportional to its base length, so increasing the base length by a factor of 2 will result in the area being multiplied by 2 as well.
Area = 1/2 x base x height The area of a triangle is directly proportional to its base (and also, actually, to it's height). Therefore, any change to the base (or it's height) is directly conferred onto that triangle's area. BY DOUBLING THE BASE OF A TRIANGLE, IT'S AREA TOO WILL DOUBLE.
By length u mean???? diagonal or height.... it doesnt have length If you meant all the lengths of the sides- the area would be 4A (the area (A) times by four).
The area of the parallelogram is quadrupled.
in a triangle double area and divide by base in a rectangle divide area by base
Area of a triangle = base * height / 2 Therefore the base = Area * 2 / height
The area of the parallelogram is quadrupled.
#include<iostream> struct shape { virtual double area () const = 0; }; struct triangle : shape { triangle (double b, double h): base (b), height (h) {} double base, height; double area () const override { return base * height / 2; } }; struct circle : shape { circle (double r): radius (r) {} double radius; double area () const override { return 4 * atan(1) * radius * radius; } }; struct rectangle : shape { rectangle (double w, double h): width (w), height (h) {} double width, height; double area () const override { return width * height; } }; int main() { triangle t (10, 5); std::cout << "triangle with base " << t.base << " and height " << t.height << " has area " << t.area() << std::endl; circle c (5); std::cout << "circle with radius " << c.radius << " has area " << c.area() << std::endl; rectangle r (10, 5); std::cout << "rectangle with width " << r.width << " and height " << r.height << " has area " << r.area() << std::endl; }