Yes, exactly - that's how it works.
The electrical force between two charged objects decreases as the distance between them increases. This relationship is described by Coulomb's Law, which states that the force is inversely proportional to the square of the distance between the charges.
The electrical force between two charged objects is inversely proportional to the square of the distance between them, according to Coulomb's law. So if the distance between the objects increases by a factor of 4, the electrical force would decrease by a factor of 16 (4^2).
When the distance between objects decreases, the electrical force between them increases. This is because the force of attraction or repulsion between charged objects is inversely proportional to the square of the distance between them, following Coulomb's law. Thus, as the distance decreases, the force strengthens.
Less distance --> more force.
A charged object exerts an electric force on other charged objects. This force can be either attractive or repulsive, depending on the charges of the objects involved. It follows Coulomb's law, which describes the relationship between the charges and the distance between the objects.
... the gravitational force between them, and the electrical force if the objects are charged.
The electrical force between two charged objects decreases as the distance between them increases. This relationship is described by Coulomb's Law, which states that the force is inversely proportional to the square of the distance between the charges.
The electrical force between two charged objects is inversely proportional to the square of the distance between them, according to Coulomb's law. So if the distance between the objects increases by a factor of 4, the electrical force would decrease by a factor of 16 (4^2).
When the distance between objects decreases, the electrical force between them increases. This is because the force of attraction or repulsion between charged objects is inversely proportional to the square of the distance between them, following Coulomb's law. Thus, as the distance decreases, the force strengthens.
Less distance --> more force.
Increasing the distance between the two charged objects will decrease both the electrical force and gravitational force acting between them. The strength of these forces decreases as the distance between the objects increases, according to the inverse square law.
A charged object exerts an electric force on other charged objects. This force can be either attractive or repulsive, depending on the charges of the objects involved. It follows Coulomb's law, which describes the relationship between the charges and the distance between the objects.
No, objects do not have to be touching each other to exert electrical force. The force between charged objects can be exerted through electric fields, which can act over a distance. This force diminishes with distance according to Coulomb's Law.
Fe = kq1q2 / r2 where k = 1/4πε, (ε is the electrical permittivity of free space), q1 and q2 are the two point charges, and r is the distance between the point charges. Therefore, electrical force varies inversely with distance, or to be more specific, they follow an inverse-square relationship.
The electrostatic force between two charged objects is inversely proportional to the distance of separation between the two objects. An Increase in the separation distance between objects decreases the force of attraction or repulsion between the objects.
You can calculate the electrical force between two charged objects using Coulomb's law equation: F = k * |q1 * q2| / r^2, where F is the force between the charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb's constant.
The electric force between two charged objects decreases by a factor of four when the distance between them is doubled. This is because the electric force is inversely proportional to the square of the distance between the charges.