The electric force between two charged objects decreases by a factor of four when the distance between them is doubled. This is because the electric force is inversely proportional to the square of the distance between the charges.
The repulsive force between two negatively charged balloons decreases by a factor of 4 when the distance between them is doubled. This is based on the inverse square law of electric force, where the force is inversely proportional to the square of the distance between the charges.
If the distance between two particles is doubled, the electric force between them decreases by a factor of 4. This is because the electric force is inversely proportional to the square of the distance between the particles, according to Coulomb's Law.
The repulsive force between two negatively charged balloons is inversely proportional to the square of the distance between them, according to Coulomb's Law. Therefore, if the distance is doubled, the repulsive force will decrease by a factor of 4.
The electric force between two charged objects is decreased by a factorof 4 if you double the distance between the objects, from the formulaF=(q1*q2)/(4*Pi*Eo*r^2).
The electric force between two objects decreases to one-fourth of the original force if the distance between them is doubled. This is because the electric force is inversely proportional to the square of the distance between the charges.
The repulsive force between two negatively charged balloons decreases by a factor of 4 when the distance between them is doubled. This is based on the inverse square law of electric force, where the force is inversely proportional to the square of the distance between the charges.
If the distance between two particles is doubled, the electric force between them decreases by a factor of 4. This is because the electric force is inversely proportional to the square of the distance between the particles, according to Coulomb's Law.
The repulsive force between two negatively charged balloons is inversely proportional to the square of the distance between them, according to Coulomb's Law. Therefore, if the distance is doubled, the repulsive force will decrease by a factor of 4.
The electric force between two charged objects is decreased by a factorof 4 if you double the distance between the objects, from the formulaF=(q1*q2)/(4*Pi*Eo*r^2).
The electric force between two objects decreases to one-fourth of the original force if the distance between them is doubled. This is because the electric force is inversely proportional to the square of the distance between the charges.
I am not sure but i thinks they are:Positive chargeNegative charge
By increasing the distance between them by sqrt(2).
The electric force will be quarter of its strength.
If the distance between two objects is doubled, the gravitational force between them decreases by a factor of 4. This is because the gravitational force is inversely proportional to the square of the distance between the objects.
When the distance between two objects is doubled, the strength of gravity decreases to one-fourth of its original value. This is because gravity follows an inverse square law, where the gravitational force is inversely proportional to the square of the distance between the objects.
If the magnitude of both charges is doubled and the distance between them is also doubled, the force between them will remain the same. This is because the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Doubling both charges and distance cancels each other out in terms of force.
Doubled