There are a minimum of 5 sheep. 4 ahead of the rear, 4 behind the front, and one in the middle of two others.
Theres 9 sheep. Because there's a sheep, then you put four behind and four in front and that same sheep in the beginning is the middle one. So that's just 9 sheep.
i think the same
4 sheep 2+2=4 2 sheep: they are both in front and in back ^^
There can be a maximum of 4 birds in this scenario. Two birds in front, one bird in the middle, and two behind.
either 3 or 5
three.
Well, honey, if there's one cat in the middle, and two cats behind it, and two cats in front of it, that adds up to a grand total of 5 cats. Math might not be your strong suit, but at least you've got some feline friends to keep you company.
100 feet
at a set of red lights. how many feet should you be behind the vehicle in front of you?
1.. sheep
3
3
There are four ducks: (in a single file row)The front two ducks are "in front of two ducks"; the rear two ducks are "behind two ducks"; and the central two ducks are between the duck at the front and the duck at the end, hence they are "between two ducks".
i think 30