239, since each of the 39 numbers may or may not be included in the result set. If we exclude the option that no number is chosen, the answer is 239-1.
Just 1.
4 of them. In a combination the order of the numbers does not matter.
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
26x26x26x10x10x10 = 17,576,000
252 combinations, :)
If the order of the numbers are important, then this is a simple combination problem. There are 10 possible numbers to choose from for the first number. Then there are 9 options for the second number. Then there are 8 options for the third, and so on. Thus, the number of possible combinations can be calculated as 10x9x8x7x6x5. This comes out at 151,200 possible combinations.
Formula: nPr where n is the number of things to choose from and you choose r of them 17P3 = 17!/ (17-3)! = 4080
There are 167960 combinations.
86,450
Just 1.
There are: 17C5 = 6188
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
10,000
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
56 combinations. :)
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.
4582