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500 W power
50J /10 s =5 W
500 USD
The energy used in 24 hours by a 60 watt bulb would be 60 x 24 = 1440 watts or 1.44 kWsAnswerExpressed in kilowatt hours, a 60-W lamp would use (60/1000) x 24 = 1.44 kW.hExpressed in megajoules, a 60-W lamp would use 60 x (60x 60 x 24) = 5.18 MJ
Computer power supplies (PSU's) have a variety of ratings including as low as 200 W and as high as 1200 W. The power rating of a computer's PSU depends on the devices installed on the computer.
Power = Force x displacement/time = 500 x 1000 / 120 = 4166.67 W
As of 2009: 43 w/ 7 wins, 28 w/ 5 wins, 21 w/ 4 wins, (88 15 24 all tied w/ 3wins)
Power = Work ÷ time Work = Force * distance Power = Force * distance ÷ time Distance ÷ time = velocity Power = Force * velocity This equation is used when you know the power and velocity. 500 = F * 20 F = 500/20 = 25 N
Watts measures power. It is abbreviated simply with a W. It is energy used (or work) over time. Thank you. So what does 1 lb = 4.45 N mean using the label used for power? If Watts measures power and is abbreviated with a W and is the label that is used for power, then what is the label used for Work?
The equation that needs to be used is I = W/E. Amps = Watts/Volts. Amps = 500/240 = 2.08 amps.
means iron rods with 500 W steel
Perimeter, P = 96 ft.Area, A = 500 ft^2.A = LW500= LWL = 500/WP = 2L + 2W96 = 2L + 2W substitute 500/W for L;96 = 2(500/W) + 2W divide by 2 to both sides;48 = 500/W + W multiply by W to both sides;48W = 500 + W^20 = 500 + W^2 - 48W or,W^2 - 48W + 500 = 0W = [48 +,- square root of [48^2 - (4)(1)(500)]/2W = [48 +,- square root of (2304 -2000)]/2W = (48 +,- square root of 304)/2W = (48 + 17.436)/2 or W = (48 - 17.436)/2W = 65.436/2 or W = 30.564/2W = 32.718 ft or W = 15. 282 ftL = 500/W = 500/32.718 or L = 500/15.282L = 15.282 ft or L = 32.718 ft