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When was Gildemeister AG created?
Gildemeister AG was created on 1870-10-01.
How do you say im going in Irish?
Tá mé ag dul
How many moles of silver (Ag) are present in a sample of 3.8 10 to the power of twenty four atoms Ag?
The answer is 6,31 moles Ag.
When was Open Systems AG created?
Open Systems AG was created on 1990-10-25.
How many moles of Ag contain 4.4910e23 atoms Ag?
To find the number of moles, we first need to calculate the number of moles of Ag atoms using Avogadro's number (6.022 x 10^23 atoms/mol). Number of moles = 4.4910e23 atoms Ag / (6.022 x 10^23 atoms/mol) ≈ 0.746 moles of Ag.
How many moles of Ag contains 4.591025 atom of Ag?
Quite a few moles of silver if you mean, 4.59 X 10^25 atoms of silver. 4.59 X 10^25 atoms silver (1 mole Ag/6.022 X 10^23) = 76.2 moles of silver ----------------------------
What happened to your account if im not open it along time in tagged?
what happened to my account in tagged if im not open it along time ag in tagged
How many mols are there in 5.42x10 to the 24 of atoms Ag?
5.42 X 10^24 atoms silver ( 1mole Ag/6.022 X 10^23) = 9.00 moles of silver
How many moles of Ag contains 4.59x10 to the power of 25 atoms of Ag?
76.2 mol Ag
How long does it take for your ag doll to ship to your house?
just wait for it. im sure it will came[incouragemant]
How do you separate the word imagination by dots?
There are five syllables like so: im-ag-i-na-tion.
Calculate the molar solubility of AgBr in a 3.0 x 10-2 M silver nitrate AgNO3 solution?
AgBr + Ag(NO)3 ----------> Ag+ + Br- Disregard Ag(NO)3 b/c of the common ion Ag and the fact that (NO)3 is a spectator ion. You use the Ksp of AgBr from the index in your book that equals 5.0*10^-13 If you look at your above equation, Ksp = [Ag] [Br] You know Ksp = 5.0*10^-13 You have also been given the concentration of Ag from Ag(NO)3 = 3.0*10^-2. You use this number because remember NO3 is always a spectator ion so [Ag] will equal the [Ag(NO)3] You equation should look like this. (Forget about doing the I.C.E on this one. Its not necessary. 5.0*10^-13-= [3.0*10^-2] [Br] Simply solve for [Br] by dividing 5.0*10^-13 by 3.0*10^-2. [Br] = 1.66*10^-11. Round for sig figs to = 1.7*10-11
