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The net ionic equation for iron II chloride (FeCl2) and copper (Cu) is: Fe2+ (aq) + Cu(s) → Fe(s) + Cu2+ (aq)
molecular equation: CuSO4 (aq)+Fe (s) --> Cu(s) + FeSO4(aq) net ionic equation: Cu2+(aq) + Fe2+ (s) --> Cu2+(s) + Fe2+(aq) spectator ion: Sulfate Ion (SO42-)
The molar mass of Fe2O3 is 55.845 (molar mass of iron)*2+16(molar mass of oxygen)*3, which comes out to be 159.69 grams per mole. Multiply that by the number of moles, and the answer is 223.57 grams.
Ferroin indicator is used in the redox titration of Mohr's salt as it changes color when the Fe2+ ions are completely oxidized to Fe3+ ions. This color change helps in determining the end point of the titration, where all the Mohr's salt has been oxidized and no more Fe2+ ions are present.
Oxidant half reaction: 2H+ + 2e- --> H2 Reductant half reaction: Fe --> Fe2+ + 2e- Tribune ions: 2Cl- --> 2Cl-
When an iron nail is dipped in copper sulfate solution, a displacement reaction occurs. The iron nail will displace the copper from the copper sulfate solution to form iron sulfate solution and copper metal deposits on the nail. This reaction is represented by the equation: Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s).
There are two well known types of "blood colors". The color of the blood is closely related to the oxygen molecules. O2 molecules can be bound in different ways: by the ferrous heme groups of the globins (e.g., myoglobin and hemoglobin); or by two Cu+ ions held in close proximity by six His side chains in hemocyanins. Fe2+ and Cu+ ions and ferrous heme groups free in solution do not bind reversibly; instead, they oxidized to the Fe3+ and Cu2+ forms. Under these circumstances, when Fe2+ is oxidized to Fe3+ acquires a red color, this is the reason why blood is red in upper organisms, those that have hemoglobin. On the other hand, when Cu+ oxidizes to Cu2+ turns to blueish color. In lower organisms (e.g., crustacea) the blood turns blueish when is exposed to oxygen. In resume, we have two blood colors, red and blueish, when it's oxidized.
Cu2+(aq) + 2e- → Cu(s) and Fe(s) → Fe2+(aq) + 2e-
Iron (Fe) undergoes oxidation when it loses electrons to form Fe2+ ions. This process involves the loss of electrons by iron atoms to form Fe2+ ions, which have a 2+ charge. The iron atoms are oxidized from an oxidation state of 0 to an oxidation state of +2 when they lose electrons.
Cu2+ e.g. CuS04 is blue in colour Fe2+ e.g. FeSO4 is green in colour Fe3+ e.g. Fe2O3 is brown in colourCorrect me if I'm wrong
The equation is: Fe2(SO4)3 + 6LiOH --> 3Li2SO4 + Fe(OH)3
When iron ions react with potassium permanganate, the iron ions are oxidized, and the potassium permanganate is reduced. The overall reaction results in the formation of iron(III) ions and manganese dioxide.