It has no meaning in C++. The name "cant" is undefined and there is no "std::cant" name defined by the C++ standard library. It's most-likely a user-defined name, but without seeing the definition or context in which it used it's impossible to say what its meaning is. In all likelihood it's a constant Boolean value, where can is true and cant is false (or vice versa depending on the logic of its usage).
++a (plus plus a) is pre-incrementing operator to aa=10;printf("%d",++a); /* it will print 11 as ++a increment first a by 1 then prints it */printf("%d",a++); /*it will printf 10 as it is post _ increment operator , it prints the value a first then increment it by 1 */
I see no reason why you can't do that. The question must be mis stated. Please clarify, and show your code.
C: there are no methods in C. C++: no.
c is procedure oriented and c++ is object oriented & much newer.
If a + b + c + d + 80 + 90 = 100, then a + b + c + d = -70.
A discriminant that is less than zero.
Because "plus" has a specific meaning in arithmetic and it is not concatenation.
The ++ in C++ refers to the postfix increment operator (operator++()). It's literal meaning is "the successor to C", in reference to the C language upon which the C++ language is based.
It doesn't. Void has the same meaning in both.
Name of a compiler (and IDE) from Borland.
runtime error
++a (plus plus a) is pre-incrementing operator to aa=10;printf("%d",++a); /* it will print 11 as ++a increment first a by 1 then prints it */printf("%d",a++); /*it will printf 10 as it is post _ increment operator , it prints the value a first then increment it by 1 */
33 dollars 99 cents plus tax
I believe that's usually treated as an axiom, meaning you don't prove it.
b+b+b+c+c+c+c =3b+4c
c + c + 2c + c + c = 6c
b + b + b + c + c + c + c = 3b + 4c