Phenolphthalein indicates red for acids and blue for bases.
For any strong base phenolphthalene is best indictor during titration.
Phenolphthalein
yes it is
For titration of hci in a mixture of hcl and acetic acid, the indicator used is
Acid base titration: 0.1 M HCl and phenolphtaleine indicator (pH=>8 blue)
I don't know ... I have the same problem . I found this in a chemestry problem , and my teacher couldn't tell me the answer . He told me to search for it, but I can't find anything about the reaction between Methyl Orange and HCl .. If you could help me , please leave a message at YM : valentin_gr2008@yahoo.com Thanks !
What you are doing here is titration. You know you have a solution of HCl, but you do not know how much HCl is in it. For this you use something that can react with HCl (NaOH) and use an indicator to tell you when the reaction is complete. The reaction is pretty simple: HCl + NaOH --> H2O + NaCl You can see here that NaOH and HCl have a 1:1 mol relationship. So, lets find out how many moles of NaOH you used up with concentration = moles/volume 0.10 M NaOH = moles NaOH/ 0.0197 L NaOH solution Remember that M is in moles/L moles NaOH = 0.00197 moles Since you have a 1:1 relationship of NaOH with HCl, the 0.00197 mol applies to HCl as well. The next question works the same way, but backwards. Try doing it yourself if you understood the first part before reading my answer. Find out how many moles of HCl you have so you can find out how much moles of NaOH you need for the neutralization. 0.050 M HCl = n HCl / 0.020 L HCl soln n HCl = 0.001 mol HCl Remeber the 1:1 relationship, which gives you that n NaOH = 0.001 mol. Now all you need is the volume. 0.1 M NaOH = 0.001 mol NaOH/ Volume soln V = 0.01 L = 10 mL
yes it is
For titration of hci in a mixture of hcl and acetic acid, the indicator used is
Acid base titration: 0.1 M HCl and phenolphtaleine indicator (pH=>8 blue)
I don't know ... I have the same problem . I found this in a chemestry problem , and my teacher couldn't tell me the answer . He told me to search for it, but I can't find anything about the reaction between Methyl Orange and HCl .. If you could help me , please leave a message at YM : valentin_gr2008@yahoo.com Thanks !
What you are doing here is titration. You know you have a solution of HCl, but you do not know how much HCl is in it. For this you use something that can react with HCl (NaOH) and use an indicator to tell you when the reaction is complete. The reaction is pretty simple: HCl + NaOH --> H2O + NaCl You can see here that NaOH and HCl have a 1:1 mol relationship. So, lets find out how many moles of NaOH you used up with concentration = moles/volume 0.10 M NaOH = moles NaOH/ 0.0197 L NaOH solution Remember that M is in moles/L moles NaOH = 0.00197 moles Since you have a 1:1 relationship of NaOH with HCl, the 0.00197 mol applies to HCl as well. The next question works the same way, but backwards. Try doing it yourself if you understood the first part before reading my answer. Find out how many moles of HCl you have so you can find out how much moles of NaOH you need for the neutralization. 0.050 M HCl = n HCl / 0.020 L HCl soln n HCl = 0.001 mol HCl Remeber the 1:1 relationship, which gives you that n NaOH = 0.001 mol. Now all you need is the volume. 0.1 M NaOH = 0.001 mol NaOH/ Volume soln V = 0.01 L = 10 mL
Usually used to calculate the concentration of one of two reagents (e.g. HCl, being titrated with NaOH), a burette is used to run a volume of HCl into a conical flask containing NaOH and an acid-base indicator, stopping when the indicator changes colour to indicate neutraliasation. The value of HCl added is read and recorded from the burette - this is usually a 'rough' reading, with subsequent titrations then performed until two concordant results are achieved (within 0.1cm3) and averaged to get a mean. From this data - the volume of one reagent required to neutralise the other - a molar ratio can be obtained, and the unknown concentration of the reagent calculated.
HCL is used to provide the acidic conditions required in the iodometeric titration.
NaOH and HCl
Iodine solution is an efficient indicator for starch. It will go from a light brown colour to a black colour if starch is present and will stay light brown if no starch is present. Hope this Helps!
This is so since the pH at the end point of Phenolphthalein is 9.1 and methyl orange is 3.7. For a strong acid strong base titration which the end point is between 3-11 phenolphthalein is used
Both HCl and oxalic acid are acids. Therefore, since there is no alkali present, these compounds do not undergo neutralization. So there is no suitable indicators for the addition of these two reagents.
iv done the titration and the preferred indicator for such a solution is phenalphaline, use a few drops to make it go a bright luminous pink and titrate till clear, not 'cloudy'