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In the compound H2 S hydrogen has an oxidation number of 1 plus and sulfur has an oxidation number of?
In the compound H2S, hydrogen has an oxidation number of +1, and sulfur has an oxidation number of -2.
What is the oxidation number of S in Li3SO4?
The oxidation number of S in Li3SO4 is +6. This is because the oxidation number of Li is +1, the oxidation number of O is -2, and the overall charge of the compound is 0, so the oxidation number of S must be +6 to balance the charges.
What is the oxidation number of zns?
The oxidation number of ZnS (zinc sulfide) is 0. Zinc (Zn) typically has an oxidation number of +2, while sulfur (S) typically has an oxidation number of -2. In a compound like ZnS where there is no charge indicated for the compound, the total oxidation number must add up to 0.
What is the oxidation number of N in (N2H5)2SO4?
The oxidation number of N in (N2H5)2SO4 is -1. This is because the overall charge of the compound is neutral, and the oxidation number of S is +6. By using the oxidation numbers of S and O, we can determine that the oxidation number of N must be -1 to balance the charges in the compound.
What is the oxidation number of Na2S2O3?
This compound is sodium thiosulphate. S represents +6 oxidation number.
In the compound H2 S hydrogen has an oxidation number of 1 plus and sulfur has an oxidation number of?
In the compound H2S, hydrogen has an oxidation number of +1, and sulfur has an oxidation number of -2.
What is the oxidation number of S in Li3SO4?
The oxidation number of S in Li3SO4 is +6. This is because the oxidation number of Li is +1, the oxidation number of O is -2, and the overall charge of the compound is 0, so the oxidation number of S must be +6 to balance the charges.
What is the oxidation number of zns?
The oxidation number of ZnS (zinc sulfide) is 0. Zinc (Zn) typically has an oxidation number of +2, while sulfur (S) typically has an oxidation number of -2. In a compound like ZnS where there is no charge indicated for the compound, the total oxidation number must add up to 0.
What is the oxidation number of N in (N2H5)2SO4?
The oxidation number of N in (N2H5)2SO4 is -1. This is because the overall charge of the compound is neutral, and the oxidation number of S is +6. By using the oxidation numbers of S and O, we can determine that the oxidation number of N must be -1 to balance the charges in the compound.
What is the oxidation number of Na2S2O3?
This compound is sodium thiosulphate. S represents +6 oxidation number.
What is the oxidation number for s2cl2?
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
What is the oxidation number of S in the compound Na2 SO4?
The oxidation number of S in Na2SO4 is +6. This is because the oxidation number of Na is +1 and of O is -2, and the overall charge of the compound is zero. Therefore, 2(+1) + x + 4(-2) = 0, where x is the oxidation number of S, which simplifies to x = +6.
What is the oxidation number of Na2S?
The oxidation number of Na in Na2S is +1. The oxidation number of S is -2. The sum of the oxidation numbers of all atoms in a compound must equal zero.
What is the oxidation number of S in Co2S3?
The oxidation number of sulfur (S) in Co2S3 is -2. This is because oxygen (O) usually has an oxidation number of -2 and cobalt (Co) has an oxidation number of +2, so the overall charge of the compound must be neutral, making sulfur's oxidation number -2.
What is the oxidation number of Al2S3?
The oxidation number of aluminum (Al) in Al2S3 is +3, while the oxidation number of sulfur (S) is -2. Each aluminum atom has an oxidation number of +3, and each sulfur atom has an oxidation number of -2 in order to balance the charge in the compound.
What is the oxidation number of O in the compound Na2SO4?
The oxidation number of oxygen (O) in most compounds, including sulfate (SO4), is typically -2. In Na2SO4, sodium (Na) has an oxidation number of +1. To calculate the oxidation number of oxygen in the compound, you would use the equation: 2(oxidation number of Na) + oxidation number of S + 4(oxidation number of O) = 0. By plugging in the known values, you can solve for the oxidation number of oxygen in Na2SO4.
What is the oxidation number of FeSO4?
0 because all compounds have an oxidation number of 0. It's the ions (fe S O) that have oxidation numbers, The sum of these oxidation numbers always = 0 in a compound and hence a compound has a oxidation number of 0. :-) hope this helped....
