0 because all compounds have an oxidation number of 0. It's the ions (fe S O) that have oxidation numbers, The sum of these oxidation numbers always = 0 in a compound and hence a compound has a oxidation number of 0. :-) hope this helped....
Yes, FeSO4 (iron (II) sulfate) is a reducing agent. In redox reactions, it can undergo oxidation itself to reduce another substance.
FeSO4 solution is typically prepared freshly because iron (II) ions are prone to oxidation in aqueous solutions, leading to the formation of insoluble Fe(OH)2 or Fe(OH)3 precipitates. This oxidation can result in inaccurate concentration measurements and affect the experimental results. Therefore, freshly prepared FeSO4 solutions ensure the stability and reliability of the solution for experimental purposes.
In FeSO4, the oxidation number of Fe is +2, and the oxidation number of oxygen is -2. To find the oxidation number of S, we can set up an equation: 2(-2) + x + 4(-2) = 0 (overall charge of the compound is zero). Solving this equation gives the oxidation number of S as +6.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Yes, FeSO4 (iron (II) sulfate) is a reducing agent. In redox reactions, it can undergo oxidation itself to reduce another substance.
FeSO4 solution is typically prepared freshly because iron (II) ions are prone to oxidation in aqueous solutions, leading to the formation of insoluble Fe(OH)2 or Fe(OH)3 precipitates. This oxidation can result in inaccurate concentration measurements and affect the experimental results. Therefore, freshly prepared FeSO4 solutions ensure the stability and reliability of the solution for experimental purposes.
In FeSO4, the oxidation number of Fe is +2, and the oxidation number of oxygen is -2. To find the oxidation number of S, we can set up an equation: 2(-2) + x + 4(-2) = 0 (overall charge of the compound is zero). Solving this equation gives the oxidation number of S as +6.
The oxidation state of Fe in iron (II) sulfate is +2. Iron (II) sulfate is written as FeSO4, where the iron atom has lost two electrons, resulting in a +2 oxidation state.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
Oxidation number of Nb is +4. Oxidation number of O is -2.
The oxidation number for H is +1, and the oxidation number for O is -1.
MnCl2: oxidation number +2MnO2: oxidation number +4KMnO4: oxidation number +7