In assigning formal oxidation states it is necessary to consider the bonding present amongst the species involved. FeS2 was one of the earliest crystal structures solved by X-ray diffraction methods and the simple cubic crystals clearly show sulphur-sulphur bonding within [S-S]2- units. These can be viewed as derived from hydrogen disulphide, H2S2 (cf. hydrogen peroxide, H2O2). Thus FeS2 would be better described as iron persulphide rather than disulphide. In considering the material as Fe2+S22− it is clear that the oxidation state of Fe is +2 while that of each S moeity is -1. A similar problem can be posed via barium peroxide, BaO2, where the oxidation state of barium must be +2 (metal in Gp 2). What is the oxidation state of oxygen in BaO2 ?
the answer is ferrous sulphate that is the old term the new one is ion sulphate.
Fe has +3 oxidation number. Oxygen has -3 oxidation number.
Fe has an oxidation number of +2, O has an oxidation number of -2
The sulfate ion is SO42- therefore S has an oxidation number of +6 (oxygen is -2 and Fe is +2)
3+
0 because all compounds have an oxidation number of 0. It's the ions (fe S O) that have oxidation numbers, The sum of these oxidation numbers always = 0 in a compound and hence a compound has a oxidation number of 0. :-) hope this helped....
Zn has oxidation number +2; S has oxidation number -2
The oxidation number of Al is +III and S is -II.
Oxidation no of sulphur is +2.
S has an oxidation number of -2. Al is +3.
0 because all compounds have an oxidation number of 0. It's the ions (fe S O) that have oxidation numbers, The sum of these oxidation numbers always = 0 in a compound and hence a compound has a oxidation number of 0. :-) hope this helped....
Zn has oxidation number +2; S has oxidation number -2
The oxidation number of Al is +III and S is -II.
Oxidation no of sulphur is +2.
S has an oxidation number of -2. Al is +3.
oxidation number of oxygen is -2 s = +5/2
This compound is sodium thiosulphate. S represents +6 oxidation number.
Electron transfer reactions. reactions involving losing and gaining electrons
This is the thiosulfate ion. Sulfur shows +6 oxidation number.
S = +2 oxidation state cl = -1 oxidation state
The oxidation number of S in S8 is ZERO!
2-