+1 for H
+6 for S
-2 for each O
Oxidation number of h is 2
H2SO4 is a compound and as such does not have an oxidation number. The individual atoms in this compound have oxidation number +1 for each hydrogen atom, +6 for sulfur, and -2 for each oxygen atom.
+6 for S, +1 for each H, -2 for each O
H is +1, Each O is -2. So S will be +6
Sufuric acid is a molecule: it is not an element. As a whole it has oxidation number 0. With six covalent bonds with four different oxygen atoms, sulfur has +6 oxidation number. Hydrogen and oxygen have +1 and -2 oxidation numbers respectively.
Oxidation number of h is 2
+1, +6, and -2 respectively
H = +1 s = +6 o = -2
H2SO4 is a compound and as such does not have an oxidation number. The individual atoms in this compound have oxidation number +1 for each hydrogen atom, +6 for sulfur, and -2 for each oxygen atom.
H is +1, Each O is -2. So S will be +6
+6 for S, +1 for each H, -2 for each O
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
Sufuric acid is a molecule: it is not an element. As a whole it has oxidation number 0. With six covalent bonds with four different oxygen atoms, sulfur has +6 oxidation number. Hydrogen and oxygen have +1 and -2 oxidation numbers respectively.
With a few exceptions that do not apply to this formula, oxygen is always assigned a formal oxidation number of -2 per atom, and hydrogen is assigned +1 per atom. The compound as a whole must always be electrically neutral. Therefore, in this molecule, the oxidation number of the single sulfur atom must be -[-2(4) +2] or +6.
oxidation number of I is -1. oxidation number of F is +1.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
Zn has oxidation number +2; S has oxidation number -2