The oxidation number of sulfur in H2SO4 is +6. This is because each hydrogen atom has an oxidation number of +1 and each oxygen atom has an oxidation number of -2. Since the overall charge of the molecule is 0, the oxidation number of sulfur must be +6 to balance out the charges.
The oxidation number of hydrogen (H) in H2SO4 is +1.
The oxidation number of hydrogen is +1, the oxidation number of sulfur is +6, and the oxidation number of oxygen is -2. In H2SO4, there are 2 hydrogen atoms (totaling +2), 1 sulfur atom (+6), and 4 oxygen atoms (totaling -8). The sum of the oxidation numbers should equal the charge of the compound, which is 0, so the oxidation number of sulfur in H2SO4 is +6.
+1 for H +6 for S -2 for each O
The oxidation number of sulfur in sulfuric acid (H2SO4) is +6. This is because oxygen typically has an oxidation number of -2, and there are four oxygen atoms in sulfuric acid. Each hydrogen atom has an oxidation number of +1. Using this information, we can calculate that the oxidation number of sulfur must be +6 in order for the overall charge of the molecule to be neutral.
The oxidation number of sulfur in sulfur powder (S8) is 0. Each sulfur atom in the elemental form has an oxidation number of 0.
The oxidation number of hydrogen (H) in H2SO4 is +1.
The oxidation number of hydrogen is +1, the oxidation number of sulfur is +6, and the oxidation number of oxygen is -2. In H2SO4, there are 2 hydrogen atoms (totaling +2), 1 sulfur atom (+6), and 4 oxygen atoms (totaling -8). The sum of the oxidation numbers should equal the charge of the compound, which is 0, so the oxidation number of sulfur in H2SO4 is +6.
Sulphur has 6 valence electrons. So its maximum oxidation number is +6.
+1 for H +6 for S -2 for each O
The oxidation number of sulfur in sulfuric acid (H2SO4) is +6. This is because oxygen typically has an oxidation number of -2, and there are four oxygen atoms in sulfuric acid. Each hydrogen atom has an oxidation number of +1. Using this information, we can calculate that the oxidation number of sulfur must be +6 in order for the overall charge of the molecule to be neutral.
The oxidation number of sulfur in sulfur powder (S8) is 0. Each sulfur atom in the elemental form has an oxidation number of 0.
The oxidation number of sulfur in H2SO4 is +6. This is determined by assigning an oxidation number of +1 to hydrogen and -2 to oxygen. Since the overall charge of the molecule is 0, sulfur must have an oxidation number of +6 to balance the charges.
The oxidation number of sulfur can vary depending on the compound it is in. In most cases, sulfur has an oxidation number of -2, as seen in hydrogen sulfide (H2S) or sulfur dioxide (SO2). However, in some compounds such as sulfuric acid (H2SO4), sulfur can have an oxidation number of +6.
The oxidation number of H in H2SO4 is +1, the oxidation number of S is +6, and the oxidation number of O is -2. This is because the sum of the oxidation numbers in a neutral compound like H2SO4 must equal zero.
In KMnO4, Mn has an oxidation number of +7, KNO2 has N with an oxidation number of +3, and H2SO4 has S with an oxidation number of +6. In MnSO4, Mn has an oxidation number of +2, H2O has O with an oxidation number of -2, KNO3 has N with an oxidation number of +5, and K2SO4 has S with an oxidation number of +6.
The oxidation number of sulphur in H2S is 2.
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.