Oxidation number of h is 2
+1 for H +6 for S -2 for each O
The oxidation number of H in H2SO4 is +1, the oxidation number of S is +6, and the oxidation number of O is -2. This is because the sum of the oxidation numbers in a neutral compound like H2SO4 must equal zero.
The oxidation number of sulfur in H2SO4 is +6. This is determined by balancing the overall charge of the compound, which is 0, and taking into account the known oxidation numbers for hydrogen (+1) and oxygen (-2).
The oxidation number of sulfur in H2SO4 is +6. This is because each hydrogen atom has an oxidation number of +1 and each oxygen atom has an oxidation number of -2. Since the overall charge of the molecule is 0, the oxidation number of sulfur must be +6 to balance out the charges.
In H2SO4, the oxidation number of H is +1, the oxidation number of S is +6, and the oxidation number of O is -2. These numbers are determined based on the rules of assigning oxidation numbers in compounds.
+1 for H +6 for S -2 for each O
The oxidation number of H in H2SO4 is +1, the oxidation number of S is +6, and the oxidation number of O is -2. This is because the sum of the oxidation numbers in a neutral compound like H2SO4 must equal zero.
+1, +6, and -2 respectively
H = +1 s = +6 o = -2
The oxidation number of sulfur in H2SO4 is +6. This is determined by balancing the overall charge of the compound, which is 0, and taking into account the known oxidation numbers for hydrogen (+1) and oxygen (-2).
The oxidation number of sulfur in H2SO4 is +6. This is because each hydrogen atom has an oxidation number of +1 and each oxygen atom has an oxidation number of -2. Since the overall charge of the molecule is 0, the oxidation number of sulfur must be +6 to balance out the charges.
In H2SO4, the oxidation number of H is +1, the oxidation number of S is +6, and the oxidation number of O is -2. These numbers are determined based on the rules of assigning oxidation numbers in compounds.
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen is typically assigned an oxidation number of +1 and oxygen -2, leading to the equation 2(1) + x + 4(-2) = 0. Solving for x gives x = +6 for sulfur.
The oxidation number for H is almost always 1+.
H2SO4 is a compound and as such does not have an oxidation number. The individual atoms in this compound have oxidation number +1 for each hydrogen atom, +6 for sulfur, and -2 for each oxygen atom.
In KMnO4, Mn has an oxidation number of +7, KNO2 has N with an oxidation number of +3, and H2SO4 has S with an oxidation number of +6. In MnSO4, Mn has an oxidation number of +2, H2O has O with an oxidation number of -2, KNO3 has N with an oxidation number of +5, and K2SO4 has S with an oxidation number of +6.
You probably mean H2SO4, where H +1; S +6;O-2.H2SiO4 does not exist. If it did the oxidation numbers of the constituent elements would be H +1; Si +6; O -2. The compound silicic acid is H4SiO4 (not isolatable) with H +1, Si +4 and O -2.