H is +1, Each O is -2.
So S will be +6
The oxidation number of hydrogen (H) in H2SO4 is +1.
+1 for H +6 for S -2 for each O
The oxidation number of sulfur in H2SO4 is +6. This is because each hydrogen atom has an oxidation number of +1 and each oxygen atom has an oxidation number of -2. Since the overall charge of the molecule is 0, the oxidation number of sulfur must be +6 to balance out the charges.
The oxidation number of H in H2SO4 is +1, the oxidation number of S is +6, and the oxidation number of O is -2. This is because the sum of the oxidation numbers in a neutral compound like H2SO4 must equal zero.
In KMnO4, Mn has an oxidation number of +7, KNO2 has N with an oxidation number of +3, and H2SO4 has S with an oxidation number of +6. In MnSO4, Mn has an oxidation number of +2, H2O has O with an oxidation number of -2, KNO3 has N with an oxidation number of +5, and K2SO4 has S with an oxidation number of +6.
The oxidation number of hydrogen (H) in H2SO4 is +1.
+1 for H +6 for S -2 for each O
The oxidation number of sulfur in H2SO4 is +6. This is because each hydrogen atom has an oxidation number of +1 and each oxygen atom has an oxidation number of -2. Since the overall charge of the molecule is 0, the oxidation number of sulfur must be +6 to balance out the charges.
The oxidation number of H in H2SO4 is +1, the oxidation number of S is +6, and the oxidation number of O is -2. This is because the sum of the oxidation numbers in a neutral compound like H2SO4 must equal zero.
In KMnO4, Mn has an oxidation number of +7, KNO2 has N with an oxidation number of +3, and H2SO4 has S with an oxidation number of +6. In MnSO4, Mn has an oxidation number of +2, H2O has O with an oxidation number of -2, KNO3 has N with an oxidation number of +5, and K2SO4 has S with an oxidation number of +6.
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
+1, +6, and -2 respectively
In H2SO4, the oxidation number of H is +1, the oxidation number of S is +6, and the oxidation number of O is -2. These numbers are determined based on the rules of assigning oxidation numbers in compounds.
The oxidation number of hydrogen is +1, the oxidation number of sulfur is +6, and the oxidation number of oxygen is -2. In H2SO4, there are 2 hydrogen atoms (totaling +2), 1 sulfur atom (+6), and 4 oxygen atoms (totaling -8). The sum of the oxidation numbers should equal the charge of the compound, which is 0, so the oxidation number of sulfur in H2SO4 is +6.
H = +1 s = +6 o = -2
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen is typically assigned an oxidation number of +1 and oxygen -2, leading to the equation 2(1) + x + 4(-2) = 0. Solving for x gives x = +6 for sulfur.
H2SO4 is a compound and as such does not have an oxidation number. The individual atoms in this compound have oxidation number +1 for each hydrogen atom, +6 for sulfur, and -2 for each oxygen atom.