Sulphur has 6 valence electrons. So its maximum oxidation number is +6.
6+
Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.
-2 for each O, +6 for S
The oxidation number in atomic sulfur is 0. The oxidation number of sulfide ion is -2. With oxygen and other non metals, it makes numerous ions where its oxidation number varies from -2 to +6.
Atomic sulfur has oxidation number 0. The oxidation number of the sulfide ion is -2. During formation of a wide variety of compounds, the oxidation status of sulfur may differ from -2 to +6.
+6 for each sulphur. +1 for each Na; Two oxygens are as peroxides and will have -1 charge / oxidation number each. Six oxygens are as oxides and will have -2 charge each. So, 2(+1) + 2y + 2(-1) + 6(-2) = 0 Or y = +6 (the charge / oxidation number of sulphur)
Number for hydrogen is +1.Number for sulphur is +6.Number for oxygen is -2.The oxidation number for the overall ion is -1. Oxidation numbers for hydrogen and oxygen are +1 and -2 respectively. By balancing the charges, the sulfur atom is in +6 state.
Each of the hydrogen atoms in H2 has an oxidation number of 0.
+1 for each hydrogen -2 for each oxygen +6 for each sulphur
+6, because the oxidation number of oxygen is -2x3=-6
oxidation number of S is +6.It oxidize into SO4 ^-2
-2 for sulphur and +1 for each copper.