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When calculating oxidation numbers, use '-2' (oxygen) as the 'yardstick'(standard).

Since SO3 has three oxygens, then the oxygen moiety is 3 x -2 = -6

Since SO3 is a neutrally charged molecule, overall oxidation is '0'.

Hence

S + -6 = 0

Hence S = 6 is the oxudation number for sulphur.

NB Sulphur exhibits different oxidation states in different molecules.

S = 0

SO2 = 4

SO3 = 6 ( as above)

H2SO4) = 6

H2S2O7 (Oleum) = 6

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lenpollock

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1w ago
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AnswerBot

8mo ago

The oxidation number for sulfur in SO3 is +6, and the oxidation number for each oxygen atom is -2.

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Wiki User

11y ago

-2 for each O

+6 for S

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Q: What is the oxidation number for SO3?
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Related questions

What is the oxidation number for Na2SO3?

The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.


What are the oxidation numbers of SO3?

In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2.


What is the oxidation state of an individual sulfur atom in (SO3)2?

If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.


Oxidation number for each element in SO3?

In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2. The sum of the oxidation numbers must equal the overall charge of the molecule, which in this case is 0.


What is the oxidation number of the sulphur atom in SO3?

The oxidation number of the sulfur atom in SO3 is +6. Each oxygen atom is assigned an oxidation number of -2, so by balancing the charges and knowing that the overall charge of the molecule is 0, sulfur must have an oxidation number of +6.


What is the oxidation state of an individual sulfur atom in SO3?

The oxidation state of sulfur in SO3 is +6. Each oxygen atom has an oxidation state of -2, and since the overall charge of SO3 is 0, the oxidation state of sulfur must be +6 to balance out the charges.


What is the oxidation number of sulphur in caso4 so4s02s03?

For CaSO4 (calcium sulfate), the oxidation number of sulfur is +6. For SO4 (sulfate ion), the oxidation number of sulfur is +6. For SO2 (sulfur dioxide), the oxidation number of sulfur is +4. For SO3 (sulfur trioxide), the oxidation number of sulfur is +6.


What is the oxidation state of each element in SO3 -2?

Sulfur has an oxidation state of +4 in SO3^2-. Each oxygen atom has an oxidation state of -2.


What is the oxidation numbers of compounds with four elements for example NH42SO3?

In NH4₂SO3, the oxidation number of N is -3 (since H is +1), the oxidation number of S is +3, and the oxidation number of O is -2. The sum of the oxidation numbers in a neutral compound is always zero, so the oxidation number of H is +1.


What is the oxidation state for s in SO3?

The oxidation state for sulfur (S) in SO3 is +6. Each oxygen atom in SO3 has an oxidation state of -2, and since the overall molecule is neutral, the sum of the oxidation states must equal zero. Therefore, sulfur must have an oxidation state of +6 to balance the -6 from the three oxygen atoms.


What is the oxidation numbers of sulfur?

The oxidation number is 0 in elemental form. It can have other oxidation numbers as -2, +4 and +6 in its compounds such as H2S, SO2 and SO3 respectively.-2, 0, 2, 4 and 6 oxidation states


What is the valency of sulphur in SO3?

Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.