When calculating oxidation numbers, use '-2' (oxygen) as the 'yardstick'(standard).
Since SO3 has three oxygens, then the oxygen moiety is 3 x -2 = -6
Since SO3 is a neutrally charged molecule, overall oxidation is '0'.
Hence
S + -6 = 0
Hence S = 6 is the oxudation number for sulphur.
NB Sulphur exhibits different oxidation states in different molecules.
S = 0
SO2 = 4
SO3 = 6 ( as above)
H2SO4) = 6
H2S2O7 (Oleum) = 6
The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.
In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2.
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2. The sum of the oxidation numbers must equal the overall charge of the molecule, which in this case is 0.
The oxidation number of the sulfur atom in SO3 is +6. Each oxygen atom is assigned an oxidation number of -2, so by balancing the charges and knowing that the overall charge of the molecule is 0, sulfur must have an oxidation number of +6.
The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.
In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2.
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2. The sum of the oxidation numbers must equal the overall charge of the molecule, which in this case is 0.
The oxidation number of the sulfur atom in SO3 is +6. Each oxygen atom is assigned an oxidation number of -2, so by balancing the charges and knowing that the overall charge of the molecule is 0, sulfur must have an oxidation number of +6.
The oxidation state of sulfur in SO3 is +6. Each oxygen atom has an oxidation state of -2, and since the overall charge of SO3 is 0, the oxidation state of sulfur must be +6 to balance out the charges.
For CaSO4 (calcium sulfate), the oxidation number of sulfur is +6. For SO4 (sulfate ion), the oxidation number of sulfur is +6. For SO2 (sulfur dioxide), the oxidation number of sulfur is +4. For SO3 (sulfur trioxide), the oxidation number of sulfur is +6.
Sulfur has an oxidation state of +4 in SO3^2-. Each oxygen atom has an oxidation state of -2.
In NH4₂SO3, the oxidation number of N is -3 (since H is +1), the oxidation number of S is +3, and the oxidation number of O is -2. The sum of the oxidation numbers in a neutral compound is always zero, so the oxidation number of H is +1.
The oxidation state for sulfur (S) in SO3 is +6. Each oxygen atom in SO3 has an oxidation state of -2, and since the overall molecule is neutral, the sum of the oxidation states must equal zero. Therefore, sulfur must have an oxidation state of +6 to balance the -6 from the three oxygen atoms.
The oxidation number is 0 in elemental form. It can have other oxidation numbers as -2, +4 and +6 in its compounds such as H2S, SO2 and SO3 respectively.-2, 0, 2, 4 and 6 oxidation states
Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.